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Write an equation of the line that is perpendicular to x equals -3?
"Y = any number" is perpendicular to "x = -3".
How do you write an equation for a perpendicular line?
To write an equation for a perpendicular line, first determine the slope of the original line. If the slope of the original line is ( m ), the slope of the perpendicular line will be the negative reciprocal, ( -\frac{1}{m} ). Using the point-slope form ( y - y_1 = m(x - x_1) ), where ( (x_1, y_1) ) is a point on the new line, substitute the perpendicular slope and point to derive the equation of the perpendicular line. Finally, you can rearrange it into slope-intercept form, ( y = mx + b ), if desired.
The line given by the equation y equals -8x is perpendicular to what line?
It would be perpendicular to a line with the equation Y = 1/8 X.
Could you write the equation of the line that is perpendicular to the line given that passes through the point shown?
Yes, I could, if I knew the slope of the line given.
How do you write an equation that is perpendicular?
Line B is perpendicular to Line A if its slope is the negative reciprocal of the slope of Line A.When a linear equation is in the formy = mx + b,m is the slope, and b is the y-intercept. So, for example,y = (2/3)x + 5is perpendicular toy = (-3/2)x + 7.(The y-intercepts in these two equations are random numbers.)
Write an equation of the line that is perpendicular to x equals -3?
"Y = any number" is perpendicular to "x = -3".
How do you write an equation for a perpendicular line?
To write an equation for a perpendicular line, first determine the slope of the original line. If the slope of the original line is ( m ), the slope of the perpendicular line will be the negative reciprocal, ( -\frac{1}{m} ). Using the point-slope form ( y - y_1 = m(x - x_1) ), where ( (x_1, y_1) ) is a point on the new line, substitute the perpendicular slope and point to derive the equation of the perpendicular line. Finally, you can rearrange it into slope-intercept form, ( y = mx + b ), if desired.
How do I write an equation in slope-intercept form for a line perpendicular to the graph of the equation that passes through the x-intercept of that line?
As for example the perpendicular equation to line y = 2x+6 could be y = -1/2x+6 because the negative reciprocal of 2x is -1/2x
Can you write the equation of a line with one point on the line?
No, you need either two points, one point and a slope, one point and a y-intercept, or a y-intercept an a slope. You can also write the equation of a line with an equation of another line but you would have to know if it is parallel or perpendicular.
Write an equation of a line that is perpendicular to y equals 3x-12?
15
Write the equation of the line that has a y-intercept of 0-9 and is perpendicular to the line 3x - 9y 8?
-3x+9=y
Write the equation of a line perpendicular to the line y x - 3 and containing the point 8 -2?
y = -x + 6
The line given by the equation y equals -8x is perpendicular to what line?
It would be perpendicular to a line with the equation Y = 1/8 X.
Could you write the equation of the line that is perpendicular to the line given that passes through the point shown?
Yes, I could, if I knew the slope of the line given.
Which equation represents a line perpendicular to the graph of 3x-6y12?
Solve the line equation for "y", to get it in slope-intercept form. You can immediately read the slope from this equation.Divide -1 by (slope of this first line) to get the slope of the second line - the one perpendicular to the given line. Write an equation for any line with this slope.
How do you write an equation that is perpendicular?
Line B is perpendicular to Line A if its slope is the negative reciprocal of the slope of Line A.When a linear equation is in the formy = mx + b,m is the slope, and b is the y-intercept. So, for example,y = (2/3)x + 5is perpendicular toy = (-3/2)x + 7.(The y-intercepts in these two equations are random numbers.)
Perpendicular line of y23x 5?
To find the equation of a line that is perpendicular to ( y = 23x + 5 ), we first identify the slope of the given line, which is 23. The slope of a line that is perpendicular to it is the negative reciprocal, so it would be ( -\frac{1}{23} ). If we have a point through which the perpendicular line passes, we can use the point-slope form ( y - y_1 = m(x - x_1) ) to write the equation, where ( m = -\frac{1}{23} ).
