"Y = any number" is perpendicular to "x = -3".
It would be perpendicular to a line with the equation Y = 1/8 X.
Yes, I could, if I knew the slope of the line given.
Line B is perpendicular to Line A if its slope is the negative reciprocal of the slope of Line A.When a linear equation is in the formy = mx + b,m is the slope, and b is the y-intercept. So, for example,y = (2/3)x + 5is perpendicular toy = (-3/2)x + 7.(The y-intercepts in these two equations are random numbers.)
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"Y = any number" is perpendicular to "x = -3".
As for example the perpendicular equation to line y = 2x+6 could be y = -1/2x+6 because the negative reciprocal of 2x is -1/2x
No, you need either two points, one point and a slope, one point and a y-intercept, or a y-intercept an a slope. You can also write the equation of a line with an equation of another line but you would have to know if it is parallel or perpendicular.
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It would be perpendicular to a line with the equation Y = 1/8 X.
-3x+9=y
y = -x + 6
Yes, I could, if I knew the slope of the line given.
Solve the line equation for "y", to get it in slope-intercept form. You can immediately read the slope from this equation.Divide -1 by (slope of this first line) to get the slope of the second line - the one perpendicular to the given line. Write an equation for any line with this slope.
Line B is perpendicular to Line A if its slope is the negative reciprocal of the slope of Line A.When a linear equation is in the formy = mx + b,m is the slope, and b is the y-intercept. So, for example,y = (2/3)x + 5is perpendicular toy = (-3/2)x + 7.(The y-intercepts in these two equations are random numbers.)
The standard equation for a straight line is y = mx + c. Let this be the equation of the original line. Note that m and c are known values. Let the given point coordinates be (a,b)Two straight lines are perpendicular if the product of their gradients (slopes) is -1.The slope (m1) of the perpendicular line is therefore m1 = -1/mWhen y = b then x = a so the equation for the perpendicular line is y = m1x + d, and substituting gives : b = -a/m + d and this will enable d to be calculated.NOTE : In the absence of information for the equation of the original line and the coordinates of the given point then this is a general rather than a specific answer.
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