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What is the slope of a line perpendicular to the line with equation y 4x 5?
Wiki User
∙ 11y ago
If you mean: y = 4x+5 then the perpendicular slope is -1/4
Wiki User
∙ 11y ago
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What is the slope of a perpendicular line 4x plus y equals 2?
-- The slope of the graph of [ 4x + y = 2 ] is -4.-- The slopes of perpendicular lines are negative reciprocals.-- The slope of any line perpendicular to [ 4x + y = 2 ] is 1/4 .
What is the perpendicular distance from the point of 7 and 5 that meets the straight line equation of 3x plus 4y equals 0 on the Cartesian plane showing work?
Equation: 3x+4y = 0 => y = -3/4x Perpendicular slope: 4/3 Perpendicular equation: 4x-3y-13 = 0 Equations intersect at: (2.08, -1.56) Distance from (7, 5) to (2.08, -1.56) = 8.2 units using the distance formula
What is the equation and its perpendicular bisector equation of the line whose end points are at -2 3 and 1 -1 on the Cartesian plane?
Points: (-2, 3) and (1, -1) Midpoint: (-0.5, 1) Slope: -4/3 Perpendicular slope: 4/3 Equation: 3y = -4x+1 Perpendicular bisector equation: 4y = 3x+5.5
How do you get the perpendicular to the equation 4x-3y equals 7?
Write the equation of the given line in standard form: y = mx + c so: 3y = 4x - 7 or y = 4/3x - 7/3 The slope of the given line is 4/3. The slope of the line perpendicular to it is the negative reciprocal (change the sign and flip the fraction over). ie the perpendicular has slope -3/4 So the equation of the perpendicular is of the form y = -3/4x + d or 4y = - 3x + 4d or 3x + 4y = 4d. To evaluate the value of the constant d (or 4d) you will need one point on the perpendicular line. Substitute the coordinates of that point for x and y in the above equation and you've got 4d.
What is the equation of the line passing through - 2 -3 and is perpendicular to the line 4x plus 3y -5 equals 0?
If: 4x+3y-5 = 0 then y = -4/3x+5/3 Slope is -4/3 and so the perpendicular slope is 3/4 Perpendicular equation: y--3 = 3/4(x--2) => 4y--12 = 3x+6 => 4y = 3x-6
What line is perpendicular to 4x-3y12?
The equation has been distorted in the question (as usual on this site). The general idea is to solve the equation for "y"; read off the slope from the resulting equation; then divide minus 1 by this slope to get the slope of the perpendicular line.
What is the slope of every line perpendicular to the graph of this equation 4x plus 5y equals 7?
4x+5y = 7 5y = -4x+7 y = -4/5x+7/5 in slope intercept form So the slope of the perpendicular line is plus 5/4
What is the slope of a line perpendicular to the line whose equation is 3x plus 4y equals 12?
4y= -3x + 12 y = -3/4x + 3 The perpendicular slope is 4/3
What is the slope of the line that is perpendicular to y - 4x 3?
If you mean: y = -4x+3 then the perpendicular slope is 1/4
What is the equation of the line passing through the point -2 -3 and is perpendicular to the line 4x plus 3y -5 equals 0?
Perpendicular equation: 4x +3y -5 = 0 Perpendicular slope: -4/3 Slope of line: 3/4 Point of line: (-2, -3) Equation of line: y - -3=3/4(x - -2) => 4y - -12=3x - -6 => 4y = 3x -6 Therefore the equation of the line is: 4y = 3x -6 or 3x -4y -6 = 0
What equation describes a line that passes through the point (-14) and is perpendicular to the line 4x-3y-9?
If you mean point (-1, 4) and equation of 4x-3y = -9 then y = 4/3x+3 Slope of equation: 4/3 Perpendicular slope: -3/4 Perpendicular equation: y-4 = -3/4(x--1) => 4y = -3x+13
What is the slope of the line that has the equation 4x plus 2y equals 12?
what is the slope of the line that has the equation 4x+2y=12?
What is the slope of a perpendicular line 4x plus y equals 2?
-- The slope of the graph of [ 4x + y = 2 ] is -4.-- The slopes of perpendicular lines are negative reciprocals.-- The slope of any line perpendicular to [ 4x + y = 2 ] is 1/4 .
What is the slope of the line perpendicular to the line 4x plus 2y equals 6?
4x+2y = 6 2y = -4x+6 y = -2x+3 Perpendicular slope is 1/2
Which of the following line is perpendicular to y 4x plus 2?
If you mean: y = 4x+2 then the line perpendicular to it will have a slope of -1/4
What is the perpendicular distance from the point of 7 and 5 that meets the straight line equation of 3x plus 4y equals 0 on the Cartesian plane showing work?
Equation: 3x+4y = 0 => y = -3/4x Perpendicular slope: 4/3 Perpendicular equation: 4x-3y-13 = 0 Equations intersect at: (2.08, -1.56) Distance from (7, 5) to (2.08, -1.56) = 8.2 units using the distance formula
What is the equation and its perpendicular bisector equation of the line whose end points are at -2 3 and 1 -1 on the Cartesian plane?
Points: (-2, 3) and (1, -1) Midpoint: (-0.5, 1) Slope: -4/3 Perpendicular slope: 4/3 Equation: 3y = -4x+1 Perpendicular bisector equation: 4y = 3x+5.5
