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* Calculate the slope of the line to which it is perpendicular to.* Divide -1 by this slope, since perpendicular lines have slopes that, when you multiply them together, give you a product of -1.

* Finally, use the slope-point equation to determine the equation of the line.

Q: What is the equation of the line passing through the point -2 -3 and is perpendicular to the line 4x plus 3y -5 equals 0?

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y = 1/3x+4/3

Known equation: 5x -2y = 3 or y = 5/2x -3/2 Slope of equation: 5/2 Slope of perpendicular equation: -2/5 Perpendicular equation: y --4 = -2/5(x -3) => 5y = -2x -14 Perpendicular equation in its general form: 2x+5y+14 = 0

The line "x = 6" will be perpendicular to any line "y = C", where C is any constant. That means that the line which is perpendicular to "x=6" and passes through [-4, 5] will be "y = 5"

The question is not quite clear but one equation will be y = 3x+6 and the other equation will have a slope of minus 1/3

It works out in its general form as: 3x-4y-6 = 0

Related questions

y=-x

y = 1/3x+4/3

Known equation: 5x -2y = 3 or y = 5/2x -3/2 Slope of equation: 5/2 Slope of perpendicular equation: -2/5 Perpendicular equation: y --4 = -2/5(x -3) => 5y = -2x -14 Perpendicular equation in its general form: 2x+5y+14 = 0

The equation will be perpendicular to the given equation and have a slope of 3/4:- Perpendicular equation: y--3 = 3/4(x--2) => 4y--12 = 3x--6 => 4y = 3x-6 Perpendicular equation in its general form: 3x-4y-6 = 0

3x-4y-6 = 0

7x-y-28 = 0

The line "x = 6" will be perpendicular to any line "y = C", where C is any constant. That means that the line which is perpendicular to "x=6" and passes through [-4, 5] will be "y = 5"

Known equation: 5x-2y = 3 or y = 5/2x -3/2 Slope of known equation: 5/2 Slope of perpendicular equation: -2/5 Perpendicular equation: y- -4 = -2/5(x-3) => 5y =-2x-14 Perpendicular equation in its general form: 2x+5y+14 = 0

y = -5x

5x - 10 = -20This equation can be restated as 5x = -10 : x = -2This is the equation of a straight line perpendicular to the x axis and passing through the point x = -2. There is no y intercept and the slope is indeterminate.

If: 4x+3y-5 = 0 then y = -4/3x+5/3 Slope is -4/3 and so the perpendicular slope is 3/4 Perpendicular equation: y--3 = 3/4(x--2) => 4y--12 = 3x+6 => 4y = 3x-6

It would be perpendicular to a line with the equation Y = 1/8 X.