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Equation: 3x+4y = 0 => y = -3/4x

Perpendicular slope: 4/3

Perpendicular equation: 4x-3y-13 = 0

Equations intersect at: (2.08, -1.56)

Distance from (7, 5) to (2.08, -1.56) = 8.2 units using the distance formula

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8y ago
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8y ago

I think the following should work:

1. Get the slope of the given line.2. Divide -1 by that slope to get the slope of a line perpendicular to it.

3. Find the equation of the line with this perpendicular slope (from step 2), and going through the given point.


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Q: What is the perpendicular distance from the point of 7 and 5 that meets the straight line equation of 3x plus 4y equals 0 on the Cartesian plane showing work?
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What is the perpendicular distance from the point of 2 4 on the Cartesian plane to the straight line equation of y equals 2x plus 10 showing key stages of work?

1 Equation: y = 2x+10 2 Perpendicular equation works out as: 2y = -x+10 3 Point of intersection: (-2, 6) 4 Distance is the square root of: (-2-2)2+(6-4)2 = 2 times sq rt of 5


What is the perpendicular distance from the point of 7 5 to the straight line whose equation is 3x plus 4y minus 16 equals 0?

Straight line equation: 3x+4y-16 = 0 Perpendicular equation: 4x-3y-13 = 0 Point of intersection: (4, 1) Distance: (7-4)2+(5-1)2 = 25 and the square root of this is the perpendicular distance which is 5 units of measurement


What is the perpendicular distance from the point 4 -2 to the straight line of 2x -y -5 equals 0?

Perpendicular equation: x+2y = 0 Point of intersection: (2, -1) Perpendicular distance: square root of 5


What is the perpendicular distance from the point 7 and 5 to the straight line equation of 3x plus 4y minus 16 equals 0?

Straight line equation: 3x+4y-16 = 0 Perpendicular equation: 4x-3y-13 = 0 Point: (7, 5) Equations intersect: (4, 1) Perpendicular distance: square root of [(7-4)2+(5-1)2] = 5


What is the perpendicular distance from the point 19 29 that meets the straight line equation 3y equals 9x plus 18 on the Cartesian plane showing work and answer to an appropriate degree of accuracy?

If: 3y = 9x+18 then y = 3x+6 with a slope of 3 Perpendicular slope: -1/3 Perpendicular equation: y-29 = -1/3(x-19) => 3y = -x+106 Both equations intercept at: (8.8, 32.4) Perpendicular distance: square root of (8.8-19)^2+(32.4-29)^2 = 10.75 rounded

Related questions

What is the perpendicular distance from the point of 2 4 to the straight line of y equals 2x plus 10 on the Cartesian plane?

The perpendicular distance from (2, 4) to the equation works out as the square root of 20 or 2 times the square root of 5


What is the perpendicular distance from the point 2 4 to the straight line equation of y equals 2x plus 10 on the Cartesian plane?

It works out as: 2 times the square root of 5


What is the other term for the straight line in a cartesian plane?

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What is the perpendicular distance from the point of 2 4 on the Cartesian plane to the straight line equation of y equals 2x plus 10 showing key stages of work?

1 Equation: y = 2x+10 2 Perpendicular equation works out as: 2y = -x+10 3 Point of intersection: (-2, 6) 4 Distance is the square root of: (-2-2)2+(6-4)2 = 2 times sq rt of 5


What is the perpendicular distance from the point of 7 5 to the straight line whose equation is 3x plus 4y minus 16 equals 0?

Straight line equation: 3x+4y-16 = 0 Perpendicular equation: 4x-3y-13 = 0 Point of intersection: (4, 1) Distance: (7-4)2+(5-1)2 = 25 and the square root of this is the perpendicular distance which is 5 units of measurement


What is the perpendicular distance from the point 4 -2 to the straight line of 2x -y -5 equals 0?

Perpendicular equation: x+2y = 0 Point of intersection: (2, -1) Perpendicular distance: square root of 5


What is the perpendicular distance from the point 7 and 5 to the straight line equation of 3x plus 4y minus 16 equals 0?

Straight line equation: 3x+4y-16 = 0 Perpendicular equation: 4x-3y-13 = 0 Point: (7, 5) Equations intersect: (4, 1) Perpendicular distance: square root of [(7-4)2+(5-1)2] = 5


What is the perpendicular distance from the point 19 29 that meets the straight line equation 3y equals 9x plus 18 on the Cartesian plane showing work and answer to an appropriate degree of accuracy?

If: 3y = 9x+18 then y = 3x+6 with a slope of 3 Perpendicular slope: -1/3 Perpendicular equation: y-29 = -1/3(x-19) => 3y = -x+106 Both equations intercept at: (8.8, 32.4) Perpendicular distance: square root of (8.8-19)^2+(32.4-29)^2 = 10.75 rounded


What is the relation between straight lines and linear equations?

The graph, in the Cartesian plane, of a linear equation is a straight line. Conversely, a straight line in a Cartesian plane can be represented algebraically as a linear equation. They are the algebraic or geometric equivalents of the same thing.


How do you solve slope intercept?

Plot its straight line equation on the Cartesian plane


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It is the equation of a straight line plotted on the Cartesian plane.


What is the equation of a straight line that cuts through the middle of the points of -1 3 and -2 -5 at right angles on the Cartesian plane showing work?

The equation will be a perpendicular bisector equation of the given points:- Points: (-1, 3) and (-2, -5) Midpoint: (-3/2, -1) Slope: 8 Perpendicular slope: -1/8 Perpendicular equation: y--1 = -1/8(x--3/2) => y = -1/8x-3/16-1 Therefore the perpendicular bisector equation is: y = -1/8x -19/16