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Q: What is the slope of a line that is perpendicular to the line with equation y equals -5x plus 8?

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The slope is -0.2

12

For the line 2x + y = 8 , the slope equals ( -2 ) so the required slope of the line which is perpendicular to it is equal to (+1/2 )

-1/5

-5

negative 1

It is: -1/2

the slope will be positive 1.5x the whole equation is y=4.5+1.5x

- 1/3

It is -1/2

3x+y = 4 y = -3x+4 Perpendicular slope: 1/3

4y= -3x + 12 y = -3/4x + 3 The perpendicular slope is 4/3

There is no y-intercept or slope for this given equation, because its graph is a vertical line perpendicular to the x-axis.

It will be the positive reciprocal of -2 which is 1/2

Slope of a line perpendicular to x-y=16

The slope of the perpendicular is -(1/2) .

Slope of given line = -3 Therefore, slope of perpendicular = 1/3

Slope of the given line is 3/7 So slope of perpendicular line is -7/3

Get the slope of the given line, by putting it into slope-intercept form. Then you can divide minus one by this slope, to get the slope of any perpendicular line.

Slope of given line = 3 So slope of perpendicular = -1/3

If you mean: y = 4x+5 then the perpendicular slope is -1/4

If you mean: y = 5x-2 then the perpendicular slope is -1/5

The line x = -4 is vertical, so a line that is perpendicular to it is horizontal, so its slope is 0.

Perpendicular equation: 4x +3y -5 = 0 Perpendicular slope: -4/3 Slope of line: 3/4 Point of line: (-2, -3) Equation of line: y - -3=3/4(x - -2) => 4y - -12=3x - -6 => 4y = 3x -6 Therefore the equation of the line is: 4y = 3x -6 or 3x -4y -6 = 0

The equation has no slope. The graph of the equation is a straight line with a slope of -1 .