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Q: What is the slope of a line which is perpendicular to the line that has an equation of y equals x plus 13?

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The slope is -0.2

For the line 2x + y = 8 , the slope equals ( -2 ) so the required slope of the line which is perpendicular to it is equal to (+1/2 )

-1/5

-5

It is: 1/5

It is: -1/2

It is -1/2

the slope will be positive 1.5x the whole equation is y=4.5+1.5x

There is no y-intercept or slope for this given equation, because its graph is a vertical line perpendicular to the x-axis.

Get the slope of the given line, by putting it into slope-intercept form. Then you can divide minus one by this slope, to get the slope of any perpendicular line.

Slope of a line perpendicular to x-y=16

- 1/3

It will be the positive reciprocal of -2 which is 1/2

3x+y = 4 y = -3x+4 Perpendicular slope: 1/3

If you mean: y = 4x+5 then the perpendicular slope is -1/4

If you mean: y = 5x-2 then the perpendicular slope is -1/5

The equation has been distorted in the question (as usual on this site). The general idea is to solve the equation for "y"; read off the slope from the resulting equation; then divide minus 1 by this slope to get the slope of the perpendicular line.

Slope of given line = -3 Therefore, slope of perpendicular = 1/3

Slope of the given line is 3/7 So slope of perpendicular line is -7/3

The line x = -4 is vertical, so a line that is perpendicular to it is horizontal, so its slope is 0.

4y= -3x + 12 y = -3/4x + 3 The perpendicular slope is 4/3

5

Take the negative reciprocal of the lines slope you want it to be perpendicular to. For example y = 3x +2; perpendicular line slope is -1/3.

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