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Which equation describes the line with slope 4 that contains the point 7 2?
y = 4x - 26
What is the equation of a line through the point 9 1 that has the slope of three?
3x - y - 26 = 0
What are the equations for the line (-26) (43)?
If you mean points of (-2, 6) and (4, 3) Then its slope is -1/2 and its equation is 2y = -x+10
What is the slope of the line represented by the table below x y -2 -9 0 5 1 12 3 26 7 54?
To find the slope of the line represented by the given points, we can select any two points from the table. For example, using the points (0, 5) and (3, 26), the slope ( m ) can be calculated using the formula ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Substituting the values, we get ( m = \frac{26 - 5}{3 - 0} = \frac{21}{3} = 7 ). Therefore, the slope of the line is 7.
What is the slope of the line 2y plus 8x equal 26?
-4
What is the equation of a line with coordinates of 3 -4 and is perpendicular to the line of 5x-2y equals 3?
Equation of given line: 5x - 2y = 3In slope intercept form, that is: 2y = 5x - 3or y = 5/2*x - 3/2So gradient of given line = 5/2Therefore, gradient of perpendicular line = -1/(5/2) = -2/5Also, the point (3, -4) is on this lineSo equation is: y - (-4) = -2/5*(x - 3)y + 4 = -2/5*(x - 3)5y - 20 = -2x + 62x + 5y = 26Equation of given line: 5x - 2y = 3In slope intercept form, that is: 2y = 5x - 3or y = 5/2*x - 3/2So gradient of given line = 5/2Therefore, gradient of perpendicular line = -1/(5/2) = -2/5Also, the point (3, -4) is on this lineSo equation is: y - (-4) = -2/5*(x - 3)y + 4 = -2/5*(x - 3)5y - 20 = -2x + 62x + 5y = 26Equation of given line: 5x - 2y = 3In slope intercept form, that is: 2y = 5x - 3or y = 5/2*x - 3/2So gradient of given line = 5/2Therefore, gradient of perpendicular line = -1/(5/2) = -2/5Also, the point (3, -4) is on this lineSo equation is: y - (-4) = -2/5*(x - 3)y + 4 = -2/5*(x - 3)5y - 20 = -2x + 62x + 5y = 26Equation of given line: 5x - 2y = 3In slope intercept form, that is: 2y = 5x - 3or y = 5/2*x - 3/2So gradient of given line = 5/2Therefore, gradient of perpendicular line = -1/(5/2) = -2/5Also, the point (3, -4) is on this lineSo equation is: y - (-4) = -2/5*(x - 3)y + 4 = -2/5*(x - 3)5y - 20 = -2x + 62x + 5y = 26
What is the slope for points (14) (26) and (38)?
If you mean points of (1,4) (2, 6) and (3, 8) then the slope is 2 and the equation is y = 2x+2
What is the equation of the tangent line that touches the circle x squared plus y squared -6x plus 4y equals 0 at the point of 6 -4 on the Cartesian plane?
Equation: x² + y² -6x +4y = 0 Completing the squares: (x-3)² + (y+2)² = 13 Centre of circle: (3, -2) Contact point: (6, -4) Slope of radius: -2/3 Slope of tangent: 3/2 Tangent equation: y - -4 = 3/2(x-6) => 2y - -8 = 3x-18 => 2y = 3x-26 Tangent line equation in its general form: 3x-2y-26 = 0
What is the slope of line passing through the points (35) and (-26)?
If you mean points of (-2, -1) and (3, 5) then the slope is 6/5
What is the equation of the tangent line that touches the circle x squared plus 10x plus y squared -2y -39 equals 0 at the point of 3 2 on the Cartesian plane showing work?
First find the slope of the circle's radius as follows:- Equation of circle: x^2 +10x +y^2 -2y -39 = 0 Completing the squares: (x+5)^2 + (y-1)^2 -25 -1 -39 = 0 So: (x+5)^2 +(y-1)^2 = 65 Centre of circle: (-5, 1) and point of contact (3, 2) Slope of radius: (1-2)/(-5-3) = 1/8 which is perpendicular to the tangent line Slope of tangent line: -8 Tangent equation: y-2 = -8(x-3) => y = -8x+26 Tangent equation in its general form: 8x+y-26 = 0
What is the maximum number of drainage fixtures units allowed on a 2'' diameter drain line?
The maximum number of drainage fixture unit on a 2" drain line depends on the slope of the drain line. 21 units are allowed if the slope is 1/4' per foot, and 26 units are allowed if the slope of the line is 1/2" per foot.
What is the tangent equation line of the circle x2 plus 10x plus y2 -2y -39 equals 0 at the point of contact 3 2 on the Cartesian plane?
Equation of circle: x^2 +10x +y^2 -2y -39 = 0 Completing the squares: (x+5)^2 +(y-1)^2 = 65 Center of circle: (-5, 1) Slope of radius: 1/8 Slope of tangent line: -8 Point of contact: (3, 2) Equation of tangent line: y-2 = -8(x-3) => y = -8x+26 Note that the tangent line meets the radius of the circle at right angles.
