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What is the point-slope equation of the line with slope three over two that goes through the point -3 5?
It is: y-5 = 1.5(x--3) => y = 1.5x+9.5
What is equation of a horizontal line through the point negative 2 and three?
The equation is [ y = 3 ].
What is the equation of a line perpendicular to y equals negative three x plus four that passes through -1 6?
You solve this type of problem using the following steps. 1) Write your original equation in slope-intercept form, that is, solved for "y". (The line is already in that form in this case). You can read off the slope directly: in an equation of the form: y = mx + b m is the slope. 2) Calculate the slope of the perpendicular line. Since the product of the slopes of perpendicular lines is -1, you can divide -1 by the slope you got in part (1). 3) Use the generic equation y - y1 = m(x - x1), for a line that has a given slope "m" and passes through point (x1, y1). Replace the given coordinates (variables x1 and y1). Simplify the resulting equation, if required.
What is the point slope equation of the line that has a slope of one eighth and goes through the point two and negative three?
m = 1/8 points--- (2,-3) Point slope form. Y - Y1 = m(X - X1) Y - (-3) = 1/8(X - 2) Y + 3 = 1/8(X - 2) Y + 3 = 1/8X - 1/4 Y = 1/8X - 13/4 --------------------
What is the answer to negative three x plus y equals twelve?
This is an equation of a straight line: y = 3x + 12, which passes through the point (0,12) and has a slope of 3 {for every 1 unit increase in x, y increases by 3}
What are the three forms of a linear equation?
1. Slope-intercept form (most commonly used in graphing) y=mx+b m=slope b=y-intercept 2. Standard form ax+by=c 3. Point slope form (most commonly used for finding linear equations) y-y1=m(x-x1) m=slope one point on the graph must be (x1,y1)
How do you graph 3x plus 4y equals -4?
3x+4y=-4 can be graphed on a graphing calculator or by changing the form of the equation from standard form to slope intercept form. Rearrange the equation 4y=-3x-4 divide by 4 y=(-3/4)x-1 Now, you can simply graph the equation using the y intercept and the slope of the equation. A good point to start with is (0,-1) you know this point is the y intercept because of the standard y intercept equation y= mx+b where b is the y intercept and m is the slope. From the y intercept of (0,-1) you can then graph using the slope which is the change of y over change in x. So you would move up 3 and to the left 4 since the slope is negative. You can also move down three and to the right 4. Then continue, this process until you have the equation graphed. It should be a straight line.
Graph 3x-y equals 3?
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Three methods in graphing linear equation?
table of values,x and y-intercept and slope and y-intercept
How do you find another possible set of coordinates of a point that has a slope of 2?
If you know one point on a graph and you also know the slope of the graph, you can use the point-slope equation to create the y-intercept form of the line. Doing this will allow you to plug in values for x or y to get any point on the graph. For example, say that the slope of the line is 2 and a point on the line is (3,2). The point-slope form is y - y1 = m(x - x1). Plug in (3,2) and the slope to get y - 2 = 2(x - 3). That simplifies to y = 2x - 4. I want to see what y-value falls on the line at x = 5, so I plug that in. I get y = 6. That means that there is also the point (5,6) on the graph.
How do you determine if three points are collinear?
Since any 2 points determine 1 line, take 2 of the points and find the equation of the line drawn thru these 2 points. Substitute the x and y of the either point into the equation and find the y-intercept (b) Then, substitute the x and y of the 3rd point into the equation and see if the both sides of the equation are =. (y2-y1) ÷ (x2 - x1) = slope y = slope * x + b Point # 1 = (6, 5) Point # 2 = (10, 25) Point # 3 = (12, 30) Point # 4 = (12, 35) (y2 - y1) ÷ (x2 - x1) = slope (25 - 5) ÷ (10 - 6) = slope (20) ÷ (4) = slope Slope = 5 y = m * x + b y = 5 * x + b Substitute the x and y of the point (6, 5) into the equation and find the y-intercept (b) y = 5 * x + b 5 = 5 * 6 + b 5 = 30 + b b = -25 y = 5 * x - 25 . Check your points Point # 1 = (6, 5) 5 = 5 * 6 - 25 5 = 30 - 25 OK . Point # 2 = (10, 25) 25 = 5 * 10 - 25 25 = 5 * 10 - 25 OK . Then, substitute the x and y of the 3rd point into the equation and see if the both sides of the equation are Point # 3 = (12, 30) . y = 5 * x - 25 30 = 5 * 12 - 25 30 = 60 - 25 = 35 Point # 3 = (12, 30) is not on the line . . Point # 4 = (12, 35) 35 = 5 * 12 - 25 35 = 60 - 25 =35 Point # 4 = (12, 35) is on the line
How do you make a linear equation go through three points?
In general, a linear equation CANNOT be made to go through three points. That will only happen if the three points are collinear and in that case, the equation of the line will only require two points.
