The slope is [-4 - (-2)]/[6 - 3] = [-4 + 2]/[6 - 3] = -2/3
The slope would be 2,6.
The slope of the perpendicular to the line passing through P1(3,6) and P2(5,1) is 2/5. Note: the slope of the original line is (change in y)/(change in x), yielding -5/2. The slope of the perpendicular is the negative reciprocal, 2/5
If you mean points of (-2, -1) and (3, 5) then the slope is 6/5
It is: (5-4)/(2-0) = 1/2
The line between the points (3, 4) and (2, 1) has: slope = change_in_y/change_in_x = (4 - 1)/(3 - 2) = 3/1 = 3
find the slop of the line passing through (1,5) and (0,2)
The slope would be 2,6.
30
It has not got a slope because it's a vertical straight line.
The slope of the perpendicular to the line passing through P1(3,6) and P2(5,1) is 2/5. Note: the slope of the original line is (change in y)/(change in x), yielding -5/2. The slope of the perpendicular is the negative reciprocal, 2/5
If you mean points of (2, 4) and (4, 2) then the slope is -1
If the slope is undefined, it is a vertical line. Therefore the equation is x=2.
If the line passing through these points is a straight line then it has a positive gradient.
To find the slope of a line passing through a given pair of points is found by using the point slope formula. Y(2)-Y(1) over x(2) -x(1).
Points: (1, 2) and (3, 8) Slope: 3
Slope = (8 - 0)/(0 - 4) = -2
Points: (1, 5) and (0.2)Slope: 3