If you mean points of (-6, -4) and (-2, 4) then the slope is 2
8x + 3y = 248x - 8x + 3y = -8x + 243y = - 8x + 243y/3 = (- 8x + 24)/3y = -8x/3 + 24/3y = (-8/3)x + 8 this is the slope-intercept form of the equation of the line, y = mx + b, where the slope m is -8/3 and the y-intercept b is 8.
The slope is -15/24 = -5/8
588
We want a line that passes through the points (22,0) and (-2,3)The general formula for a line is y = mx +bWhere M is our slope, and B is the y-intercept.We don't know either, so we have to use the points given to figure out 1) the slope 2) the y intercept.You can find slope by using the slope formuladifference in y's divided by the difference in x's(22,0) is (x,y) and (-2,3) is also (x,y)(0 - 3)/(22 - (-2))-3/24 = -1/8Our slope is -1/8.Now we plug m = -1/8 into the general formula y = mx +b.We also pick ONE set of points, and plug that in for x and y. (it's easier to pick smaller numbers)y = mx + b3 = (-1/8)(-2) + bNow we solve for b.3 = 1/4 + b3 - 1/4 = b12/4 - 1/4 = b (I changed 3 to a fraction to work with -1/4)11/4 = b(or 2 and 3/4)Now we know both the slope, m = -1/8 and the y-intercept, b = 11/4.We just put these into the general form of a line and we have our equation.y = mx + by = -1/8x +11/4
The slope is 5.
If you mean: (0, 0) and (2, 4) then the slope works out as 2
Your answer is 3/24 or 0.125 Slope = Rise / Run
If you mean slope of -3 and a point of (2, 4) then the equation is y = -3x+10
-24
If you mean: 12x-2y = -48 then y = 6x+24 whereas 6 is the slope and 24 is the y intercept
If 10x + 6y = 24, y = (24 - 10x)/6 = 4 - (5/3)x. The slope of a line with an equation written in this format is the coefficient of x, therefore -(5/3).
If you mean points of (-6, -4) and (-2, 4) then the slope is 2
standard form is y = mx + b where m = slope 12 x+ 4y = 24 3x + y = 6 y = -3x + 6 slope is -3
slope of a line in standard form ax + by = c is -(a/b). So, your slope would be -(2/-4) or 1/2.
If you mean points of (-2, 4) and (3, 5) then its equation works out as 5y = x+22
The slope m' of a line perpendicular to a line with slope m is such that m'm = -1 → m' = -1/m A line with slope m' through point (X, Y) has equation: y - Y = m'(x - X) → The line perpendicular to 7x - 8y = 12 through p (-3, 1) is found: 7x - 8y = 12 → 8y = 7x - 12 → y = (7/8)x - 3/2 → The slope of 7x - 8y = 12 is m = 7/8 → The slope of the perpendicular line is m' = -1/m = -1/(7/8) = -8/7 → The line through P with this slope m' is: y - 1 = -8/7(x - -3) → y = (-8/7)x - 24/7 + 1 → y = (-8/7)x - 17/7 This can be rearranged into: y = (-8/7)x - 17/7 → 7y = -8x - 17 → 7y + 8x + 17 = 0