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5.

To leave a remainder of 1 when divided by 2, the number must be odd.

To leave a remainder of 2 when divided by 3, the number must also be two more than a multiple of 3.

The multiples of 3 which are odd are 1 x 3, 3 x 3, 5 x 3, etc.

The smallest odd multiple of three is 1 x 3 = 3 ⇒ required number is 3 + 2 = 5.

Q: What is the smallest number that leaves a remainder of 1 when divided by 2 and a remainder of 2 when divided by 3?

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23

Try 30

The smallest whole number that can be divided by both 3 and 6 and leaves a remainder of 1 is 7.

12*1 + 3 = 15 12*2 + 3 = 27 12*4 + 3 = 51 when 51 divided by 15 gives the remainder as 6.

It is an integer which, when divided by 2, leaves a remainder of 1.

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The smallest whole number that can be divided by both 3 and 6 and leaves a remainder of 1 is 7.

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12*1 + 3 = 15 12*2 + 3 = 27 12*4 + 3 = 51 when 51 divided by 15 gives the remainder as 6.

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