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What is the solution for limit x tends to zero tank minus sink whole divided by k?
Wiki User
∙ 13y ago
Since x is not a part of the expression, x can approach zero without any effect. So, the answer would be (tank-sink whole)/k, k<>0.
Wiki User
∙ 13y ago
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The limit of 3-x - 3x divided by 3-x plus 3x as x approaches infinity is please answer deverafroilanyahoocom?
the answer is infinte.reason:when you add the two terms ,the numerator is a quadratic equation but denominator is a linear in x ,,,, so as x tends to infinite the function tends to infinite
What is the limit of x as it approaches infinity for e to the negative 2x divided by the square root of 1-x squared?
1
Is it generally true that limit of e to the power of fx as x tends to infinity is equal to e to the power of limit of fx as x tends to infinity?
In general, for a continuous function (one that doesn't make sudden jump - the type of functions you normally deal with), the limit of a function (as x tends to some value) is the same as the function of the limit (as x tends to the same value).e to the power x is continuous. However, you really can't know much about "limit of f(x) as x tends to infinity"; the situation may vary quite a lot, depending on the function. For example, such a limit might not exist in the general case. Two simple examples where this limit does not exist are x squared, and sine of x. If the limit exists, I would expect the two expressions, in the question, to be equal.
What is the answer to limit as x approaches infinity of e raised-x squared?
limit x tends to infinitive ((e^x)-1)/(x)
How are a cone and a pyramid alike?
Start with a regular tetrahedron (triangular based pyramid). As you increase the number of sides in the base of the pyramid, the shape becomes more and more like a right cone. In the limit, the base tends to a polygon with an infinite number of sides - a circle, and the pyramid tends to a right cone.
What is limit of 1 -cos x divided by x as x approaches 0?
1
What is the infinite limit of ln 0?
If x --> 0+ (x tends to zero from the right), then its logarithm tends to minus infinity. On the other hand, x --> 0- (x tends to zero from the left) makes no sense, at least for real numbers, because the logarithm of negative numbers is undefined.
The limit of 3-x - 3x divided by 3-x plus 3x as x approaches infinity is please answer deverafroilanyahoocom?
the answer is infinte.reason:when you add the two terms ,the numerator is a quadratic equation but denominator is a linear in x ,,,, so as x tends to infinite the function tends to infinite
What is the limit of x as it approaches infinity for e to the negative 2x divided by the square root of 1-x squared?
1
Does the series 1 divided by x diverge?
No. If x tends to infinite, 1/x tends to zero.
Is it generally true that limit of e to the power of fx as x tends to infinity is equal to e to the power of limit of fx as x tends to infinity?
In general, for a continuous function (one that doesn't make sudden jump - the type of functions you normally deal with), the limit of a function (as x tends to some value) is the same as the function of the limit (as x tends to the same value).e to the power x is continuous. However, you really can't know much about "limit of f(x) as x tends to infinity"; the situation may vary quite a lot, depending on the function. For example, such a limit might not exist in the general case. Two simple examples where this limit does not exist are x squared, and sine of x. If the limit exists, I would expect the two expressions, in the question, to be equal.
What is the limit of x divided by e to the x as x approaches infinity?
Limit as x tends to ∞: x/e^xAs you can see, as x approaches infinity, the sum becomes ∞/∞. Now we use l'Hospitals rules.d/dx(x) = 1 (Derivative)d/dx(e^x) = e^x (Derivative)therefore, the sum can be written as lim x tends to ∞ 1/e^xNow as x approaches infinity, the sum = 1/∞ = 0Therefore, lim x tends to infinity: x/e^x = 0
How do I evaluate the limit sin9x divided by tan9x when x tends to 0 without using L Hospitals rule?
First to simplify matters, change y=9x. So we are looking at limit sin(y) divided by tan(y).Now lets look at right angled triangle wheresin(y) = a/ctan(y) = a/bthus we are looking at the limit of (a/c)/(a/b) = limit of b/cAs the angle y shrinks, the right angle remains constant, and the remaining angle approaches a right angle. Thus at the limit we have a triangle with equal angles and thus where b=c.As a result limit you are trying to calculate is 1.
What is the answer to limit as x approaches infinity of e raised-x squared?
limit x tends to infinitive ((e^x)-1)/(x)
Find the limit of lim sin 4x sin 6x x 0?
Unfortunately, the browser used by Answers.com for posting questions is incapable of accepting mathematical symbols. This means that we cannot see the mathematically critical parts of the question. We are, therefore unable to determine what exactly the question is about and so cannot give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "divided by", "equals" etc. As it appears, you seem to be seeking the limit of sin(4x)*sin(6x) as x tends to 0. Both components of the product tend to 0 as x tens to 0 and so the limit is 0. Bit I suspect that is not the limit that you are looking for.
What will be Limit x tends to 0 x square minus x plus 1 whole divide bi x minus sinx?
It is not possible to answer the question because it is ambiguous. The expression could be(x^2 - x + 1) / x - sinxor(x^2 - x + 1) / (x - sinx)Clearly, the answer will differ.This sort of ambiguity would have been avoided by using brackets.
What does by mean?
In maths, it tends to be short for divided by, although this may not always be the case.
