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How do I evaluate the limit sin9x divided by tan9x when x tends to 0 without using L Hospitals rule?
First to simplify matters, change y=9x. So we are looking at limit sin(y) divided by tan(y).
Now lets look at right angled triangle where
sin(y) = a/c
tan(y) = a/b
thus we are looking at the limit of (a/c)/(a/b) = limit of b/c
As the angle y shrinks, the right angle remains constant, and the remaining angle approaches a right angle. Thus at the limit we have a triangle with equal angles and thus where b=c.
As a result limit you are trying to calculate is 1.
What else can I help you with?
What is limit of 1 -cos x divided by x as x approaches 0?
1
What is the surface area of a cube if the volume is 16 cm cubed?
The length of a side is about 2.519842cm without exceeding the volume limit. Taking the side length we have ((2.519842)squared)x6=38.0976222cm squared.
Can a function have a limit at every x-value in its domain?
Yes, that happens with any continuous function. The limit is equal to the function value in this case.Yes, that happens with any continuous function. The limit is equal to the function value in this case.Yes, that happens with any continuous function. The limit is equal to the function value in this case.Yes, that happens with any continuous function. The limit is equal to the function value in this case.
If n equals 8 why is n divided by 0 undefined?
Undefined: You cannot divide by zero
Evaluate Limit x tends to 0 x minus sinx divided by tanx minus x?
lim (x→0) [(x - sin x)/(tan x - x)]Since both the numerator and the denominator have limit zero as x tends to 0, the quotient is indeterminate at 0 and of the form 0/0. Therefore, we apply the l'Hopital's Rule and the limit equalslim (x→0) [(x - sin x)'/(tan x - x)']= lim (x→0) [(1 - cos x)/(sec2 x - 1)] (form 0/0, use again the l'Hopital's Rule)= lim (x→0) [(1 - cos x)'/(sec2 x - 1)']= lim (x→0) [(0 - (-sin x)/(2sec x sec x tan x - 0)]= lim (x→0) [(sin x)/(2sec2 x tan x)] (substitute 1/cos2 x for sec2 x and sin x/cos x for tan x)= lim (x→0) [(sin x)/(2sin x/cos3 x)]= lim (x→0) [(sin x cos3 x)/2sin x]= lim (x→0) (cos3 x/2)= 1/2Thus, (x - sin x)/(tan x - x) tends to 0.5 as x tends to 0.
How do you evaluate this limit Algebraically limit as x approaches 0 of 3sinx divided by x-2tanx without using Lhospital rule?
sinx = sin0 = 0 tanx = tan0 = 0 you have 0/0 by you limit conditions
What is the infinite limit of 1 divided by ln x?
The limit should be 0.
What is the purpose of a word limit in a statement of purpose?
The purpose of a word limit in a statement of purpose is to ensure that applicants are able to concisely and effectively communicate their goals, experiences, and qualifications without providing excessive or irrelevant information. It helps admissions committees evaluate candidates efficiently and fairly.
What is the limit of x to the 4-1 divided by x-1 as x approaches 1?
The limit is 4.
Where you can download farm mania with no time limit and without ads?
where you can download farm mania without time limit and without ads
What are the ratings and certificates for Without Limit - 1995?
Without Limit - 1995 is rated/received certificates of: USA:R
How many acute care hospitals are in the Los Angeles area?
If you limit it to Los Angelse city limits the answer is 39. Ellen
How do you calculate the limit of e5x -1 divided by sin x as x approaches 0?
You can use the L'hopital's rule to calculate the limit of e5x -1 divided by sin x as x approaches 0.
What is the limit of 2sinx divided by4 as x goes to pi?
0.5
Does the limit exist for fn divided by fn-1 in the Fibonacci sequence and if so what is it?
The limit is the Golden ratio which is 0.5[1 + sqrt(5)]
How do you calculate working load limit?
There are several ways to calculate working load limit. One of these includes Minimum Breaking Load (MBL) divided by Working Load Limit (WLL) equals Working Load Limit (WLL).
What is limit of 1 -cos x divided by x as x approaches 0?
1
