answersLogoWhite

0

Find the limit of lim sin 4x sin 6x x 0?

Updated: 4/28/2022
User Avatar

Beethoventherealgeni...

Lvl 1
9y ago

Best Answer

Unfortunately, the browser used by Answers.com for posting questions is incapable of accepting mathematical symbols. This means that we cannot see the mathematically critical parts of the question. We are, therefore unable to determine what exactly the question is about and so cannot give a proper answer to your question.

Please resubmit your question spelling out the symbols as "plus", "minus", "times", "divided by", "equals" etc.

As it appears, you seem to be seeking the limit of sin(4x)*sin(6x) as x tends to 0.

Both components of the product tend to 0 as x tens to 0 and so the limit is 0. Bit I suspect that is not the limit that you are looking for.

User Avatar

Wiki User

9y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: Find the limit of lim sin 4x sin 6x x 0?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

What is the differentiation of 'sin 4x'?

d/dx[sin(4x)] = sin(4x) ======


Would it be possible to solve a function equal to a limit For example, lim(x→∞)=(5x^3+2)/(4x^2+1)?

yes


How will the value of sin 35 determine?

to find sin 35 here we take the angle = x=15 then 3x=45 , 4x=60 then 4x-3x=60-45 then by putting sin on rhs we will get cos 35 and sin 35 hope it helped you


How do you get to necropolis from falconreach?

if your by Lim's store, go right 4x and go down. there you have it!


What is the differentiation of say -x sine 4x?

-x*4*cos4x + (-1)*sin4x = -4xcos(4x) - sin(4x)


What is the integral of sin squared 2x?

You would probably use a power-reduction trig identity to solve this equation. This states that sin2(x) = (1 - cos(2x))/2 Therefore, sin2(2x) = (1 - cos(4x))/2, or (1/2)(1 - cos(4x)) So, ∫ (1/2)(1 - cos(4x)) dx = (1/2) ∫ (1 - cos(4x)) dx. Then, ∫ (1-cos4x)dx = x - (1/4)sin(4x) + c Now, multiply that by (1/2) to get: (x - (sin(4x)/4) + c)/2 Since c is an arbitrary constant, we have: ½(x - sin(4x) / 4) + c OR 1/8 * (4x - sin(4x)) + c


How do you find the amplitude maximum minimum and period for y equals -1 plus 3sin4x?

y = -1 + 3 sin 4xLet's look at the equation of y = 3 sin 4x, which is of the form y = A sin Bx, wherethe amplitude = |A|, and the period = (2pi)/B.So that the amplitude of the graph of y = 3 sin 4x is |3| = 3, which tell us that the maximum value of y is 3 and the minimum value is -3, and the period is (2pi)/4 = pi/2, which tell us that each cycle is completed in pi/2 radians.The graph of y = -1 + 3 sin 4x has the same amplitude and period as y = 3 sin 4x, and translates the graph of y = 3 sin 4x one unit down, so that the maximum value of y becomes 2 and the minimum value becomes -4.


How do you find the value of x with 4 sin 2x tan 5x sin 7x equals sin 4x?

Once way is to plot it out, and note the intersection points. One spot is 0.2225400023465516 Follow the Wolfram|Alpha link for more answers.


Integral of sin square x times cos square x?

(1/8)(x-sin 4x)


How long is each side of a 28 inch regular decagon?

It is 9.1 inches (approx). L*[sin(x) + sin(2x) + sin(3x) +sin(4x)] = 28 inches where x = 360/10 = 36 degrees. Since x = 36 deg, sin(x) = sin(4x) and sin(2x) = sin(3x) So L*[2sin(x) + 2sin(2x)] = 28 inches L*[sin(x) + sin(2x)] = 14 inches L* 1.539 = 14 approx so that L = 9.098 inches or 9.1 inches, approx.


If fx equals sinsinx use a graph to find a upper bound for absf4x?

f(x) = sin(sin(x)). We don't really care about the 'x' or the '4x' or even the 'abs'. If we're looking at sin(sin(anything)), the greatest value the inside sine can have is 1, and the outer sine can't be greater than the Sin(1) which is roughly 0.8415.(assuming we're talking radians).


Find the value of x: 2(4x + 4) = (4x - 12)?

2(4x + 4) = (4x - 12) 8x + 8 = 4x - 12 8x - 4x + 8 = 4x - 4x - 12 4x + 8 = -12 4x + 8 - 8 = -12 - 8 4x = -20 4x/4 = -20/4 x = -5