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3x2 - 9x = -5; add 5 to both sides, in order to use the quadratic formula
3x2 - 9x + 5 = 0; a = 3, b = -9, and c = 5
x = [-b ± √(b2 - 4ac)]/(2a)
x = {-(-9) ± √[(-9)2 - 4(3)(5)]}/[(2)(3)] = [9 ± √(81 - 60)]/6 = [9 ± √21)/6
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