log of the square root of 'y' = 1/2 sqrt(y)
y6
5x times the square root of y
2x square root 6x y squared
Yes, if x and y = 1 √1 + √1 = √1 + 1 1 + 1 = 1 + 1 QED
square root (y) / Square root (3) root (y) / 1.73
x=y
log of the square root of 'y' = 1/2 sqrt(y)
y6
5x times the square root of y
X^1/2 + Y^1/2 Essentially it is just the square root of x plus the square root of y, there's no real way of simplifying that.
If x is a multiplication symbol, then square root of 36(4)y^2 = square root of(4^2)(2^2)(y^2) = (4)(2)(y) = 8y If it is a variable x, then square root of 36x4y^2 = square root of (4^2)(x)(2^2)(y^2) = (4)(2)(y)(square root of x)= 8y(square root of x)
2x square root 6x y squared
Algebraically if we have a number 'x^2' Then its square is (x^2)^2 = x^4 For the square root of x^2 = +/-x
Yes, if x and y = 1 √1 + √1 = √1 + 1 1 + 1 = 1 + 1 QED
The square root of a number x is one that, when multiplied by itself gives the value x. So if y * y = x then y is the square root of x. But, (-y)*(-y) also equals x. So -y is also a square root of x. Thus, given any positive number, x, there are two numbers, y and -y whose square is x. So both of them are square roots of x. One of y and -y must be greater than 0 and the other must be less than 0. The one that is less than 0 is the negative square root. As an example, 4 * 4 = 16 and (-4) * (-4) = 16 so both, 4 and -4 are square roots of 16. -4 is the negative square root while 4 is the positive square root (also called the principal square root).
y = 36