answersLogoWhite

0


Best Answer

X^1/2 + Y^1/2

Essentially it is just the square root of x plus the square root of y, there's no real way of simplifying that.

User Avatar

Wiki User

11y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: What is the square root of x plus the square root of y?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

If x equals y can square root x plus square root y equals square root x plus y?

Yes, if x and y = 1 √1 + √1 = √1 + 1 1 + 1 = 1 + 1 QED


What is the square root of x squared plus y squared?

X + y


What is the square root of root x plus 3 times the square root of x?

y = sqrt X + 3sqrt X is the same as y = 4 sqrt X


What is the square root of x - y divided by square root of x y?

x=y


The difference between square and square roots?

Algebraically if we have a number 'x^2' Then its square is (x^2)^2 = x^4 For the square root of x^2 = +/-x


What is 2 square root x - 3 square root y over square root x plus square root y?

5


What does x equal in y equals x squared plus 4?

y equals x plus 4 when y equals 0 then x equals 2i i is the square root of negative 1


Simplify square root of 36x4y2?

If x is a multiplication symbol, then square root of 36(4)y^2 = square root of(4^2)(2^2)(y^2) = (4)(2)(y) = 8y If it is a variable x, then square root of 36x4y^2 = square root of (4^2)(x)(2^2)(y^2) = (4)(2)(y)(square root of x)= 8y(square root of x)


What is the derivative of y equals square root of 8x plus square root of 4x?

y=(8x).5 + (4x).5 = (2+2sqrt(2))x.5 y'=(1 + sqrt(2))/sqrt(x)


How do you simplify square root of x plus 10 plus square root of 10 divided by x algebraically?

simplify the square foor of 49 times x to the third time y to the sixth times the absolute value of z squared


What is the domain and range of y equals the square root of x plus 6?

Domian is x>-6 Range is y> or equal to 0


What is the derivative of y equals square root of x when x is positive?

y = square root of x y = x(1/2) y' = (1/2)x(1/2 - 1) y' = (1/2)x(-1/2) y' = (1/2)(square root of x)