If both angles are 180, their sum is 360!If both angles are 180, their sum is 360!If both angles are 180, their sum is 360!If both angles are 180, their sum is 360!
360 + 180 = 540
Each angle theta is (n-2)/n) x 180 degrees The sum of all angles is nx theta = (n-2) x 180 sum = 180 n - 360 sum + 360 = 180 n n = (sum + 360)/180 = sum/180 + 2 So you divide sum by 180 then add 2
360 because ALL quadrilaterals have an angle sum of 360
because INTERIOR ANGLE 180 AND the exterior angle 180 so 180+180=360
The sum of all of the angles in a trapezoid is 360 degrees. The sum of interior angles for an n-sided polygon is equal to 180(n-2) which, in this case, is 180(4-2) = 360.
360 degress which is the same as the sum of the interior angles of a quadrilateral. 360 + 8 x 180 = 1800°
180 * n - 360
The sum of the interior angles of a quadrilateral is 360 degrees (not 180). The sum of the exterior angles is also 360 degrees. Whether the quadrilateral is convex or concave is not relevant.
False, the sum of the angles in a parallelogram is 360 degrees.
The total sum of angles around a point are 360 degrees.
Sum of included angles of any polygon = (180 x n) - 360 (where n is number of sides). For a hexagon the sum is (180 x 6) - 180 = 720 degrees.
Because it complies with the formula: (n-2)*180 = sum of interior angles A quadrilateral has 4 sides and so: (4-2)*180 = 360 degrees
Sum of exterior angles: 360 degrees Sum of interior angles: 180 degrees The square of its hypotenuse is equal to the sum of its base squared plus its height squared.
There are a number of ways of proving that the sum of the interior angles of a polygon, which has n sides, is (n - 2)*180 degrees.In the case of a quadrangle, n = 2 and so the angle sum is (4 - 2)*180 = 2/180 = 360 deg.
Any quadrilateral may be split into two triangles; the sum of internal angles of any triangle is 180 degrees; so the sum of internal angles of a quadrilateral will then be the double of the sum of internal angles of a triangle: 180 x 2 = 360.
If you cut any quadrilateral along one of its diagonals, the figures formed are two triangles. Since the sum of the angles of a triangle is 180 degrees, then the sum of the angles of two triangles is 2(180) = 360 degrees. For this reason, the sum of the angles of a quadrilateral is 360 degrees.
30 * 180 - 360 = 5040
12,600 degrees -- and it doesn't matter whether the 72-gon is regular or not. The sum of the exterior angles (from an extension of each side to the next) of any polygon is always 360 degrees. Therefore the sum of the interior angles is always (number of sides) * 180 - 360. 72 * 180 - 360 = 70 * 180 = 12,600.
If you are allowed to "know" that the sum of the interior angles of a triangle is 180 degrees, then you can construct the diagonal of the four sided figure making two triangles and when you add 180 to 180 you get 360.
180 subtracted by 360 = -180
The sum of the interior angles of a trapezoid is 360 degrees. That is because n=180(n-2) and n=4 because there are four sides, so then 180(4-2)=360