44 + 28 + 23 = 95
5 + 23 = 28
51.
5 + 23 = 28 11 + 17 = 28
It is 21 because 21+23 = 44
5 + 23 = 28or11 + 17 = 285 + 23 = 28or11 + 17 = 285 + 23 = 28or11 + 17 = 285 + 23 = 28or11 + 17 = 28
The sum of the first seven positive INTEGERS is 28. The sum of the fisrt seven positive numbers is infinitesimally small.
The total sum is: 23+6+15 = 44
They are: 24 28 32 36 40 44 and 48
The numbers are 24, 25, 26, 27, 28 and their sum is 130
81/4 + 17/11 = 8 + 1 + 1/4 + 7/11 = 9 + 11/44 + 28/44 = 939/44
square of 5=5*5=25 Now sum of 23 and square of 5=23+25=48 Now one third of sum of 23 and square of 5=48/3 =16 Hence 16 is answer
60 - 28 = 32; 32/2 = 16. This is the smaller number so the other is 16 + 28 ie 44.