Q: What is the sum of 72 and twice 25?

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23, 24 & 25 :)

You probably want to know "What are the 3 consecutive whole numbers whose sum is 72 ?" They are 23, 24, and 25.

If the unknown number is q then: 2q+25 = 72

The numbers are 23, 24 and 25.

let x be the first integer. therefore (x-3)=(36-x)*2. (36-x)*2 expanded=(72-2x) (x-3)=(72-2x). 3x-3=72. 3x=75 x=25. 36-25=11. Answer: the smaller number is 11.

Related questions

The sum of -47 and -25 is -72.

23, 24 & 25 :)

You probably want to know "What are the 3 consecutive whole numbers whose sum is 72 ?" They are 23, 24, and 25.

47 + 72 = 119.

Sum is 25, difference is 13 So twice the bigger is 25+13 = 38 ie bigger is 19 and twice the samller is 25-13 = 12 ie smaller is 6 So their product = 19*6 = 114

If the unknown number is q then: 2q+25 = 72

Twice with a remainder of 22 or 2.88 times

72.

The numbers are 23, 24 and 25.

let x be the first integer. therefore (x-3)=(36-x)*2. (36-x)*2 expanded=(72-2x) (x-3)=(72-2x). 3x-3=72. 3x=75 x=25. 36-25=11. Answer: the smaller number is 11.

Twice the sum of 'x' and 'y' . . . 2(x+y) The sum of twice 'x' and 'y' . . . (2x+y)

Let the nos. Are X-1,X & X+1 Now (X-1) + X +(X+1) = 72 3X= 72 X =24 So the nos are 23,24&25