23, 24 & 25 :)
You probably want to know "What are the 3 consecutive whole numbers whose sum is 72 ?" They are 23, 24, and 25.
If the unknown number is q then: 2q+25 = 72
let x be the first integer. therefore (x-3)=(36-x)*2. (36-x)*2 expanded=(72-2x) (x-3)=(72-2x). 3x-3=72. 3x=75 x=25. 36-25=11. Answer: the smaller number is 11.
The numbers are 23, 24 and 25.
The sum of -47 and -25 is -72.
23, 24 & 25 :)
You probably want to know "What are the 3 consecutive whole numbers whose sum is 72 ?" They are 23, 24, and 25.
47 + 72 = 119.
Sum is 25, difference is 13 So twice the bigger is 25+13 = 38 ie bigger is 19 and twice the samller is 25-13 = 12 ie smaller is 6 So their product = 19*6 = 114
If the unknown number is q then: 2q+25 = 72
72.
The numbers are 23, 24 and 25.
let x be the first integer. therefore (x-3)=(36-x)*2. (36-x)*2 expanded=(72-2x) (x-3)=(72-2x). 3x-3=72. 3x=75 x=25. 36-25=11. Answer: the smaller number is 11.
Twice the sum of 'x' and 'y' . . . 2(x+y) The sum of twice 'x' and 'y' . . . (2x+y)
Let the nos. Are X-1,X & X+1 Now (X-1) + X +(X+1) = 72 3X= 72 X =24 So the nos are 23,24&25
2(x+y) is twice the sum of x and y, and 2x+y is the sum of twice x and y