Write three numbers whose sum is 10 in all horizontal vertical and diagonal?
The sum of two numbers will almost always be greater than either number. The only exception would be when dealing with two negative numbers.
Not always, if the smaller number is 0 or a negative number. Then their sum will be equal or less than the greater number.
Let's take a look at this. For any integer n, 2n always be even, then the next consecutive number 2n + 1 must be odd. Let add them first, 2n + 2n + 1 = 4n + 1 = 2(2n) + 1 So their sum is odd, since every even number multiplied by 2 is also even. Let's multiplied them, 2n(2n + 1) = (2n)^2 + 2n Their product is even, since every even number raised in the second power is also even, and the sum of two even numbers is even too. So the answer is that when the sum of two numbers can be odd, their product is an even number. (note that the sum of two odd numbers is even)
The sum of two odd numbers is even and the sum of an even number and an odd number is odd.So the sum of three consecutive odd numbers is odd but 270 is even.Ergo there are no three consecutive odd numbers that sum to 270.Three consecutive numbers that sum to 270 are 89, 90, 91.Three consecutive even numbers that sum to 270 are 88, 90, 92.
Their sum is three times the middle number.
The greater number of the three is 26.
The smallest consecutive three numbers that total 120 are... 39, 40 & 41.
The answer to that question is 49,50,51
There are no three consecutive numbers with a sum of 170.
The sum of 3 consecutive whole numbers is always equal to 3 times the middle number in that sequence.
19, 20, 21
The three consecutive even numbers with a sum of 138 are 44, 46 and 48.
31 + 32 + 33 = 96
That doesn't work. The number has to be divisible by three. Any three consecutive numbers add up to a multiple of three.