0
1 + 150 = 151
2 + 149 = 151
Therefore, there are 75 pairs each totalling 151
Therefore, the answer is
75 X 151 = 11325.
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∙ 10y ago
Adam Griffiths
Adam Griffiths
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Find the sum of the reciprocals of two real numbers given that these numbers have a sum of 150 and a product of 40?
1/x + 1/y = (y+x)/xy But y + x = sum = 150, and xy = product = 40 So sum of reciprocals = 150/40 = 3.75
What is the sum of all odd numbers from 1 to 12000?
The sum of all the odd numbers between 1 and 12000 is 36000000.
150 as a sum of 4 square numbers?
12^2+2^2+1^2+1^2 = 144 + 4 + 1 + 1 = 150.
What is the sum from all the odd numbers from 1 to 100?
The sum of all the odd numbers from 1 through 100 is 10,000
Consider the numbers from 1-500 inclusive what is the difference between the sum of all of the even numbers and the sum of all the odd numbers?
501
What is the sum of all odd numbers from 1 to 150?
5625
What is the sum of the whole numbers from 1 to 150?
The sum is 150*151/2 = 11,325
Find the sum of the reciprocals of two real numbers given that these numbers have a sum of 150 and a product of 40?
1/x + 1/y = (y+x)/xy But y + x = sum = 150, and xy = product = 40 So sum of reciprocals = 150/40 = 3.75
What is 150 as the sum of three square numbers?
100 + 49 + 1
What are all the prime numbers 1-150?
What are prime numbers from 1-150?
What is the sum of all the numbers 1 through 200?
The sum of all the numbers 1 through 200 is 20,100.
What is the sum of all odd numbers from 1 to 12000?
The sum of all the odd numbers between 1 and 12000 is 36000000.
Sum of the all prime numbers within 1 to 100?
The sum of the all prime numbers from 1 to 100 is 1,161
150 as a sum of 4 square numbers?
12^2+2^2+1^2+1^2 = 144 + 4 + 1 + 1 = 150.
What is the sum of all odd numbers to 120000?
The sum of all odd numbers 1 to 120,000 is 14,400,000,000.
What is the sum from all the odd numbers from 1 to 100?
The sum of all the odd numbers from 1 through 100 is 10,000
What is the sum of all prime numbers between 1 to 11?
The sum of all prime numbers between 1 and 11 is 28.
