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What is the sum of all the four digit numbers formed using the digits 0 1 2 and 3 None of the two digits should be repeated?
Wiki User
∙ 12y ago
Process of solving
From these four digits '0' cannot be at first place to form four digit number
so we have 1, 2, or 3 can be at thousand's place
keeping one digit at thousand place can have 6 different four digit number
so that means
1000*6 + 2000* 6 + 3000* 6 = 36000
Now come to hundred's place we can have all four digit at this place , '0' will not contribute any thing to sum so in all four digits number 1,2,3 will be at 4 times on same place
so that means
100*4 + 200* 4 + 300 * 4= 2400
Now come to tenth's place ...same as hundred
so
10*4 + 20*4 + 30*4= 240
same for unit place
1*4 + 2*4 + 3*4= 24
in last if you add whole the total sum of all possible four digit number formed is38664
Wiki User
∙ 12y ago
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How many numbers of at least tree different digits can be formed from the integers 123456?
Numbers formed should be of at least 3 digits means they may be of 3 digits, 4 digits, 5 digits or 6 digits. There are 6 choices for digit in the units place. There are 5 and 4 choices for digits in ten and hundred’s place respectively. So, total number of ways by which 3 digits numbers can be formed = 6.5.4 = 120 Similarly, the total no.of ways by which 4 digits numbers can be formed = 6.5.4.3 = 360. the total no. of ways by which 5 digits numbers can be formed = 6.5.4.3.2 = 720. The total no.of ways by which 4 digits numbers can be formed = 6.5.4.3.2.1 = 720. So, total no.of ways by which the numbers of at least 3 digits can be formed = 120 + 360 + 720 + 720 = 1920.
How many numbers does a debit card have?
It Should Have 16 Digits
How many 3 digit numbers have at least one repeated digit?
There are a total of 900 3-digt numbers (100 thru 999); Of these there are 9x9x8 = 648 numbers that do not contain repeating digits (first position: 9 possibilities, second place 9 possibilities; the 10 digits minus the one used in the first place. and third place 8 possibilities; 10 digits minus the two used in the first and second places) So, there should be 900-648=252 3-digit numbers with at least one repeating digit.
How many ways can you arrange the digits 985 with four dif numbers?
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Notice the pattern. One digit repeated is always that number over 9. Two digits repeated is always those two digits over 99 and so on. 0.7777 repeated = 7/9 0.5454 repeated = 54/99 0.125 repeated = 125/999
How many numbers of at least tree different digits can be formed from the integers 123456?
Numbers formed should be of at least 3 digits means they may be of 3 digits, 4 digits, 5 digits or 6 digits. There are 6 choices for digit in the units place. There are 5 and 4 choices for digits in ten and hundred’s place respectively. So, total number of ways by which 3 digits numbers can be formed = 6.5.4 = 120 Similarly, the total no.of ways by which 4 digits numbers can be formed = 6.5.4.3 = 360. the total no. of ways by which 5 digits numbers can be formed = 6.5.4.3.2 = 720. The total no.of ways by which 4 digits numbers can be formed = 6.5.4.3.2.1 = 720. So, total no.of ways by which the numbers of at least 3 digits can be formed = 120 + 360 + 720 + 720 = 1920.
How many numbers does a debit card have?
It Should Have 16 Digits
How many 3 digit numbers have at least one repeated digit?
There are a total of 900 3-digt numbers (100 thru 999); Of these there are 9x9x8 = 648 numbers that do not contain repeating digits (first position: 9 possibilities, second place 9 possibilities; the 10 digits minus the one used in the first place. and third place 8 possibilities; 10 digits minus the two used in the first and second places) So, there should be 900-648=252 3-digit numbers with at least one repeating digit.
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No. Whole numbers are numbers which are "Whole" just as the term suggests. IT should not be a fraction or have any decimal digits.
When you are making 3 digit numbers with 3 digits how do you know you have found them all?
there should be six answers
How many ways can you arrange the digits 985 with four dif numbers?
985,958,895,859,589,598. It should be 6. Hope I helped. Possible you want 4 digit numbers using the digits 9 8 and 5 and you want to know how many of those there are?
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On the back of your card there should be a strip with numbers on it. The security code is the last three digits. :)
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How many prime numbers are there whose square has 5 or 6 digits?
solution: we know that there are 25 prime numbers are between 1-100 and 168 prime numbers less than 1000. 100 x 100=10000(5 digits) 999 x 999=998001(6 digits) 1000 x 1000=1000000(7 digits) so our answer should be same as the number of prime numbers between 100 to 999. hence, 168-25=143. 143 prime numbers will be there less than 1000 whose square has 5 or 6 digits.
How to turn repeating decimals into fractions?
Notice the pattern. One digit repeated is always that number over 9. Two digits repeated is always those two digits over 99 and so on. 0.7777 repeated = 7/9 0.5454 repeated = 54/99 0.125 repeated = 125/999
How do you write thirteen million and eighteen thousadn in numbers?
I could give you the answer, but it will be more fun if you try to figure it out yourself. Here are the basic rules: To the right of "millions", there should be 6 digits. In other words, write the "13" and make sure there are 6 digits to the right of these digits. To the right of the thousands, in this case, the digits "18", there should be 3 digits. Use zeroes to fill out.
