Process of solving
From these four digits '0' cannot be at first place to form four digit number
so we have 1, 2, or 3 can be at thousand's place
keeping one digit at thousand place can have 6 different four digit number
so that means
1000*6 + 2000* 6 + 3000* 6 = 36000
Now come to hundred's place we can have all four digit at this place , '0' will not contribute any thing to sum so in all four digits number 1,2,3 will be at 4 times on same place
so that means
100*4 + 200* 4 + 300 * 4= 2400
Now come to tenth's place ...same as hundred
so
10*4 + 20*4 + 30*4= 240
same for unit place
1*4 + 2*4 + 3*4= 24
in last if you add whole the total sum of all possible four digit number formed is38664
Numbers formed should be of at least 3 digits means they may be of 3 digits, 4 digits, 5 digits or 6 digits. There are 6 choices for digit in the units place. There are 5 and 4 choices for digits in ten and hundred’s place respectively. So, total number of ways by which 3 digits numbers can be formed = 6.5.4 = 120 Similarly, the total no.of ways by which 4 digits numbers can be formed = 6.5.4.3 = 360. the total no. of ways by which 5 digits numbers can be formed = 6.5.4.3.2 = 720. The total no.of ways by which 4 digits numbers can be formed = 6.5.4.3.2.1 = 720. So, total no.of ways by which the numbers of at least 3 digits can be formed = 120 + 360 + 720 + 720 = 1920.
It Should Have 16 Digits
There are a total of 900 3-digt numbers (100 thru 999); Of these there are 9x9x8 = 648 numbers that do not contain repeating digits (first position: 9 possibilities, second place 9 possibilities; the 10 digits minus the one used in the first place. and third place 8 possibilities; 10 digits minus the two used in the first and second places) So, there should be 900-648=252 3-digit numbers with at least one repeating digit.
985,958,895,859,589,598. It should be 6. Hope I helped. Possible you want 4 digit numbers using the digits 9 8 and 5 and you want to know how many of those there are?
solution: we know that there are 25 prime numbers are between 1-100 and 168 prime numbers less than 1000. 100 x 100=10000(5 digits) 999 x 999=998001(6 digits) 1000 x 1000=1000000(7 digits) so our answer should be same as the number of prime numbers between 100 to 999. hence, 168-25=143. 143 prime numbers will be there less than 1000 whose square has 5 or 6 digits.
Numbers formed should be of at least 3 digits means they may be of 3 digits, 4 digits, 5 digits or 6 digits. There are 6 choices for digit in the units place. There are 5 and 4 choices for digits in ten and hundred’s place respectively. So, total number of ways by which 3 digits numbers can be formed = 6.5.4 = 120 Similarly, the total no.of ways by which 4 digits numbers can be formed = 6.5.4.3 = 360. the total no. of ways by which 5 digits numbers can be formed = 6.5.4.3.2 = 720. The total no.of ways by which 4 digits numbers can be formed = 6.5.4.3.2.1 = 720. So, total no.of ways by which the numbers of at least 3 digits can be formed = 120 + 360 + 720 + 720 = 1920.
It Should Have 16 Digits
When multiplying numbers with significant digits, count the total number of significant digits in each number being multiplied. The result should have the same number of significant digits as the number with the fewest significant digits. Round the final answer to that number of significant digits.
There are a total of 900 3-digt numbers (100 thru 999); Of these there are 9x9x8 = 648 numbers that do not contain repeating digits (first position: 9 possibilities, second place 9 possibilities; the 10 digits minus the one used in the first place. and third place 8 possibilities; 10 digits minus the two used in the first and second places) So, there should be 900-648=252 3-digit numbers with at least one repeating digit.
A Social Security Number should only be composed of nine digits. Three digits then a dash, three more digits then another dash, and three final digits should be the only numbers.
No. Whole numbers are numbers which are "Whole" just as the term suggests. IT should not be a fraction or have any decimal digits.
there should be six answers
1) Look at the two numbers you are multiplying 2) Find both their number of significant digits 3) Multiply both numbers together normally 4) Round your answer to the same number of significant digits of the least number in the first two factors 250 x 185 250 had 2 sig. digits------ 185 has 3 sig. digits 250 has the least number of sig. digits (2) Final answer has to have 2 sig. digits Normal answer: 46250 With rounding of sig. digits: 46000
On the back of your card there should be a strip with numbers on it. The security code is the last three digits. :)
985,958,895,859,589,598. It should be 6. Hope I helped. Possible you want 4 digit numbers using the digits 9 8 and 5 and you want to know how many of those there are?
it should be on the board or the box of the board of 15 digits of letters and numbers: 1 letter + 5 numbers + 1 letter + 8 numbers.
solution: we know that there are 25 prime numbers are between 1-100 and 168 prime numbers less than 1000. 100 x 100=10000(5 digits) 999 x 999=998001(6 digits) 1000 x 1000=1000000(7 digits) so our answer should be same as the number of prime numbers between 100 to 999. hence, 168-25=143. 143 prime numbers will be there less than 1000 whose square has 5 or 6 digits.