Q: What is the sum of the digits on a standard mobile phone (0-9)?

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1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 0 = 45

1+2+3+4+5+6+7+8+9+0=45

A harshad phone number is a phone number in which the number itself is evenly divisible by the sum of the individual digits.

int Sum( int digits ) { if(digits < 10) return digits; return digits%10 + Sum(digits/10); }

Add the digits together. The sum of the digits of 23 is 5.

The sum of the digits is also a multiple of 9. And, if the sum of the digits is too large, you can sum those digits and keep going.

Add the digits together. The sum of the digits of 23 is 5.

the sum of my digits is 6? answer=60

8 is the same as the sum of the digits of its cube, 512.

The sum of the digits in 252 is 2 + 5 + 2 which equals 9.

the sum of individual digits of a given integer number

A dozen is equal to 12. The sum of the digits of 12 are 1 + 2 = 3.

The sum of your digits is the total number arrived at after adding two or more numbers.

1 + 1 = 2 The sum of the digits is therefore 2.

The sum is 22 times the sum of the three digits.

String num = Integer.toString(12345); // Insert your Integer here. int sum = 0; for(int i = 0; i < num.length(); i++){ sum += Character.digit(num.charAt(i), 10); } System.out.println(sum); // Simply prints the sum of the digits to standard out. ///// ALTERNATE SOLUTION: int num = 12345; // Insert your Integer here. int sum = 0; while (num > 0){ sum += num % 10; num /= 10; } System.out.println(sum); // Simply prints the sum of the digits to standard out.

The sum of the individual digit is itself

The digits of 330 are 3, 3 and 0, so the sum of those digits means add them up - 3+3+0=6

4

88

13

The sum of the digits in odd position minus the sum of the digits in even position is divisible by 11.

Since a dozen is 12, then the digits are 1 and 2. To get the sum, you simply add 1 + 2, which = 3.

2025.

There are 5460 five digit numbers with a digit sum of 22.

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