The positive integer factors of 1002 are: 1, 2, 3, 6, 167, 334, 501, 1002
2 x 2 x 5 x 5 = 1002 + 2 + 5 + 5 = 14
The sum is 4009005.
Exactly 1000 odd-numbers !
1001 and 1002
To compute this sum, we can use a nifty algebraic approach:Let S be the sum, so:S = 3 + 6 + 9 + 12 + ... + 996 + 999We can also write S as:S = 999 + 996 + ... + 12 + 9 + 6 + 3Adding these two equations together we get:2S = 1002 + 1002 + ... + 1002 + 1002Where there are 333 1002's in the above equation.This leads us to:2S = 1002 * 333S = 501 * 333 = 166,833.
The prime factors of 1,002 = 2 ⋅ 3 ⋅ 167
1002 and -1000 Does that count?
They are:1*1002*504*255*20and10*10
The sum of the factors of 10,752 is 32,736.
154 is the sum of the proper factors of 256.
The sum of the positive factors of 504 is: 1,560