The sum of the interior angles of a triangle is 180 deg. For a convex polygon with n sides we can divide it to n-2 triangles. So the answer, if the polygon is convex, is (13-2)*180= 1980 deg * * * * * The polygon need not be convex. The formula for the sum of the interior angles is valid as long as the polygon is simple - that it, its sides do not cross each other inside the polygon.
The sum of the interior angles of any regular polygon of n sides is equal to 180(n - 2) degrees. Divide that by the number of sides.
The formula for calculating the TOTAL of the interior angles of an n-sided polygon is: Angle Sum = 180 (n-2) degrees *For a regular convex polygon, each of the identical interior angles will be 180(n-2)/n This will also be 180 - (360/n), supplementary to the exterior angle.
Only when it is a regular polygon that all interior angles are of equal measure
Sum of interior angles of a n-gon is 180*(n-2) So for a 10-gon (decagon), the sum would be 180*8 = 1440 degrees. That is true whether the polygon is convex or not (as long as its sides do not intersect).
Only if it is a regular polygon.
All triangles and regular polygons such as squares, parallelograms, trapezoids, and rectangles are convex because each of their interior angles is less than 180o.
That is correct. For example, a hexagon is a 6 sided shape with each side equal length, an each interior angle 60°. ■
The interior angles of an 11 sided polygon add up to 1620 degrees
The sum of the exterior angles of a convex polygon which has sides and one angle at each vertex is 360 degrees.
hmm * * * * * The sum of the interior angles of an n-sided polygon is 180*(n-2) degrees. IF the polygon is equiangular, then each angles is the above sum divided by n.