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There is no set of three consecutive integers whose sum is 88.

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0258/3 = 86 so the answer has to be 84+86+88

They are 88 and 89.

88,89,90 the answer is 88, 89,90.

x + (x+1) + (x + 2) = 267 3x + 3 = 267 3x = 264 x = 88 Answer: 88, 89, 90

-45 and -43.

The numbers are 43 and 45.

The numbers are 82, 84, 86 and 88.

The numbers are -25, -23, -21 and -19.

82, 84, 86, 88

The sum of two odd numbers is even and the sum of an even number and an odd number is odd.So the sum of three consecutive odd numbers is odd but 270 is even.Ergo there are no three consecutive odd numbers that sum to 270.Three consecutive numbers that sum to 270 are 89, 90, 91.Three consecutive even numbers that sum to 270 are 88, 90, 92.

Algebraically, X = integer. X + (X + 1) = 89 2X + 1 = 89 2X = 88 X = 44 ------------so X + 1 which is 44 + 1 = 45 ( 44, 45) --------------are your consecutive integers

Two positive integers cannot have a sum which is negative!

I assume you wish to know which four consecutive even integers sum to 340. Let the smallest of the integers be x. Then the others are x+2, x+4 and x+6 and x + (x+2) + (x+4) + (x+6) = 340 iff 4x = 328 iff x = 82. So the integers are 82, 84, 86 and 88.

88 / 4 = 22 = 4 + 5 + 6 + 7... so 4(4) + 4(5) + 4(6) + 4(7) = 16 + 20 + 24 + 28 = 88

11 and 8 11+8 = 19 11*8 = 88

84 + 86 + 88 = 258

let x = integer and x + 2 next consecutive even integer x +(x +2) = 90 2x + 2 = 90 2x + 88 x = 44 and x+2 = 46 44 and 46

Since consecutive integers differ by one, let's represent them as x, x + 1, x + 2, and x + 3. So we have, x + (x + 1) + (x + 2) + (x + 3) = 94 4x + 6 = 94 4x = 88 x = 22 Thus, the numbers are 22, 23, 24, and 25. (Check:)

Sum_ap = ½ × number_of_terms × (first_term + last_term) For the first 88 multiples of three: number_of_terms = 88 first_term = 1 × 3 = 3 last_term = 88 × 3 = 264 → Sum = ½ × 88 × (3 + 264) = 44 × 267 = 11748

83, 3, 2

There is no solution. The sum MUST be an even number that is NOT divisible by 4. Negative 88 is divisible by 4

The sum of 88 and 11 is 99.

11, 13, 15 and 17(143 is 112 less than 255)The equation is (A)(A+2) = (A+4)(A+6) - 112A2 + 2A = A2 +10A +24 -1122A = 10A - 888A = 88A = 112,5,6

There are no such numbers. 15+16+17+18+19 = 85 and 16+17+18+19+20 = 90 Such question must be answered in terms of integers because otherwise the concept of consecutive cannot be used.

No four consecutive whole numbers have a sum of 360. 88 + 89 + 90 + 91 = 358 . . . too small 89 + 90 + 91 + 92 = 362 . . . too big

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