They are are 62, 63 and 64.
The integers are 24, 25 and 26.
Divide the sum of the three consecutive odd integers by 3: -273 /3 = -91. The smallest of these integers will be two less than -91 and the largest will be two more than -91, so the three consecutive odd integers will be -89, -91, and -93.
Divide the sum of the three consecutive odd integers by 3: 159/3 = 53. The smallest of these integers will be two less than 53 and the largest will be two more than 53, so the three consecutive odd integers will be 51, 53, and 55.
Divide the sum of the three consecutive odd integers by 3: 45/3 = 15. The smallest of these integers will be two less than 15 and the largest will be two more than 15, so the three consecutive odd integers will be 13, 15, and 17.
x + (x+1) + (x + 2) = 267 3x + 3 = 267 3x = 264 x = 88 Answer: 88, 89, 90
It need not be. 2 and 3 are consecutive integers and their sum is 5, not 31.
87,89,91.....87+89+91=267
Divide the sum of the three consecutive odd integers by 3: -3 /3 = -1. The smallest of these integers will be two less than -1 and the largest will be two more than -1, so the three consecutive odd integers will be -3, -1, and +1.
201
They are are 62, 63 and 64.
3 consecutive even integers whose sum is 396 are 130, 132 and 134.
a+b+c=267 simplify to one var x+(x+1)+(x+2)=267 x+x+1+x+2=267 3x+3=267 3x+3-3=267-3 3x=264 3x/3=264/3 x=88 therefore a=88 b=89 c=90
The sum of even integers cannot end with 9. why not
4 and 5
73,74,75
The integers are 16, 17 and 18.