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Q: What are 3 consecutive integers that have a sum of 267?

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They are are 62, 63 and 64.

The integers are 24, 25 and 26.

Divide the sum of the three consecutive odd integers by 3: -273 /3 = -91. The smallest of these integers will be two less than -91 and the largest will be two more than -91, so the three consecutive odd integers will be -89, -91, and -93.

The integers are 3, 4, 5 and 6.

Divide the sum of the three consecutive odd integers by 3: 159/3 = 53. The smallest of these integers will be two less than 53 and the largest will be two more than 53, so the three consecutive odd integers will be 51, 53, and 55.

Related questions

x + (x+1) + (x + 2) = 267 3x + 3 = 267 3x = 264 x = 88 Answer: 88, 89, 90

It need not be. 2 and 3 are consecutive integers and their sum is 5, not 31.

87,89,91.....87+89+91=267

They are are 62, 63 and 64.

3 consecutive even integers whose sum is 396 are 130, 132 and 134.

Divide the sum of the three consecutive odd integers by 3: -3 /3 = -1. The smallest of these integers will be two less than -1 and the largest will be two more than -1, so the three consecutive odd integers will be -3, -1, and +1.

201

73,74,75

4 and 5

The sum of even integers cannot end with 9. why not

The integers are 4, 5 and 6.

-3,-4,-5

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