I assume you wish to know which four consecutive even integers sum to 340.
Let the smallest of the integers be x. Then the others are x+2, x+4 and x+6 and
x + (x+2) + (x+4) + (x+6) = 340 iff 4x = 328 iff x = 82.
So the integers are 82, 84, 86 and 88.
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4, 6, 8, 10
No.Let the four numbers be (n-1), n, (n+1), (n+2).Their sum is 4n + 2 = 2(2n + 1)If 2000 is the sum of four consecutive integers, then:2(2n+1) = 2000⇒ 2n + 1 = 1000⇒ 2n = 999but 999 is odd, not even and so n cannot be an integer; therefore 2000 is not the sum of four consecutive integers.
The integers are 17, 19, 21 and 23.
It is -7,-6,-5,-4!
Heading upwards from -3, the four consecutive integers are -3, -1, 1, 3.-3, -1, 1 and 3.