The sum of the first 100 counting numbers (1-100) is 5,001.
106
The sum of the first 100 odd numbers is 10,000.
The sum of the first 100 prime numbers is 24,133
The sum of the 25 primes less than 100 is even (it is 1060).The first prime number is 2. Every other prime number is odd.So, of the 25 primes less than 100, one is even and 24 are odd.Any two odd numbers sum to an even number. Therefore, an even number of odd numbers has an even sum. So the sum of 24 odd numbers is even.Therefore, the sum of the 25 primes less than 100 is even.
4,950 If you pair up 1+99, 2+98, 3+97 and so on up to 49+51, you will have 49 pairs each adding to 100, and the number 50 which hasn't been included.49x100 + 50 = 4950
4990
The sum of the first 100 natural numbers is 5,001.
The sum of the first 500 odd counting numbers is 250,000.
The sum of the first 50 counting numbers, excluding zero, is 1,251.
The sum of the first 1,000 counting numbers (which excludes zero) is 500,001.
If the first number is 100 then the second number is 50 and the sum is 150. If the second number is 100 then the first number is 200 and the sum is 300. The question cannot be answered with one solution as it is currently worded.
The sum of the first six counting numbers (1-6) is 19.
1+1+1+1+1+=5 * * * * * The question did not ask for the sum of the first counting number five times! The sum of the first 5 counting numbers is 1+2+3+4+5 = 15. Such sums are known as triangular numbers.
Counting 0 as a number, it's 20. Not counting 0, it's 30.
The sum of the first 10 counting numbers (1-10) is 51.
It is 155 greater.
Sum of the first n even numbers starting with 0 (counting 0 as the first number, 2 would be the second number.... etc) is n x (n-1)