The sum of the first 1,000 counting numbers (which excludes zero) is 500,001.
The sum of the first 50 counting numbers, excluding zero, is 1,251.
The sum of the first 500 odd counting numbers is 250,000.
1+1+1+1+1+=5 * * * * * The question did not ask for the sum of the first counting number five times! The sum of the first 5 counting numbers is 1+2+3+4+5 = 15. Such sums are known as triangular numbers.
Counting 0 as a number, it's 20. Not counting 0, it's 30.
The sum of the first 10 counting numbers (1-10) is 51.
The sum of the first 100 counting numbers (1-100) is 5,001.
The sum of the first 50 counting numbers, excluding zero, is 1,251.
The sum of the first 500 odd counting numbers is 250,000.
The sum of the first six counting numbers (1-6) is 19.
1+1+1+1+1+=5 * * * * * The question did not ask for the sum of the first counting number five times! The sum of the first 5 counting numbers is 1+2+3+4+5 = 15. Such sums are known as triangular numbers.
Counting 0 as a number, it's 20. Not counting 0, it's 30.
The sum of the first 10 counting numbers (1-10) is 51.
It is 155 greater.
Sum of the first n even numbers starting with 0 (counting 0 as the first number, 2 would be the second number.... etc) is n x (n-1)
The first odd number is 1 The 1000th odd number is 1000 x 2 - 1 = 1999 Sum = number_of_numbers x (first_number + last_number) ÷ 2 = 1000 x (1 + 1999) ÷ 2 = 1000 x 2000 ÷ 2 = 1000000
The sum of the first thousand whole numbers can be calculated using the formula for the sum of an arithmetic series, which is n/2 * (first term + last term), where n is the number of terms. In this case, the first term is 1 and the last term is 1000. So, the sum would be 1000/2 * (1 + 1000) = 500 * 1001 = 500500.
4990