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In order to answer the question, its height is also required.
To find the surface area of a cylindrical ring or torus, you can use the formula A = 2πrh, where r is the average radius of the ring and h is the height or thickness of the ring. In this case, the average radius is (16mm + 10mm)/2 = 13mm and h can be any desired value. Therefore, the surface area of the cylindrical ring or torus is 2π(13mm)(h).
The area of the cylindrical part of the surface is equal to the perimeter of the base multiplied by the height. The perimeter of a circle with diameter 12 is pi times the diameter; therefore, the area of the cylindrical part of the surface is 12 X 15 X pi = 5.6 X 102. (Only two significant digits are justified, since there are only two in the primary data.) Sometimes the surface area is considered to include the upper lower bases of the cylinder along with the cylindrical area. The area of a circle is pi multiplied by the square of the radius, which is half the diameter. (12/2)2 X pi = 1.1 X 102. If both bases are added to the cylindrical area, the total area is 7.8 X 102, to the justified number of significant digits.
Total surface area of a cylinder = (2*p*radius2)+(pi*diameter*height)Total surface area = 1130.973355 or 1131 square feet to the nearest square foot.
diameter X pi = circumference circumference X height = area
In order to answer the question, its height is also required.
S=pi x dxD S=3.14 x 3 x 40,82 S=384,5244 or rounded 385 mm
The surface area, to the nearest tenth, of a sphere that has a diameter of 14 inches is: 615.8 inches2
surface area = (pai) x (DO 2 - DI 2)/4 = 3.14 (16 x 16 - 10 x 10)/4 = 3.14 x 156 mm = 489.84 square mm
To find the surface area of a cylindrical ring or torus, you can use the formula A = 2πrh, where r is the average radius of the ring and h is the height or thickness of the ring. In this case, the average radius is (16mm + 10mm)/2 = 13mm and h can be any desired value. Therefore, the surface area of the cylindrical ring or torus is 2π(13mm)(h).
If your ring has an outer radius of 8 mm and an inner one of 5 mm, you will have pi times (routside)2 minus pi times (rinside)2 or about 122.522 square millimeters of area on the top of the ring. Double that if you add in the surface area of the bottom. As to the sides (the inside and outside), we cannot calculate them without a thickness.
The area of the cylindrical part of the surface is equal to the perimeter of the base multiplied by the height. The perimeter of a circle with diameter 12 is pi times the diameter; therefore, the area of the cylindrical part of the surface is 12 X 15 X pi = 5.6 X 102. (Only two significant digits are justified, since there are only two in the primary data.) Sometimes the surface area is considered to include the upper lower bases of the cylinder along with the cylindrical area. The area of a circle is pi multiplied by the square of the radius, which is half the diameter. (12/2)2 X pi = 1.1 X 102. If both bases are added to the cylindrical area, the total area is 7.8 X 102, to the justified number of significant digits.
725.466
Total surface area of a cylinder = (2*p*radius2)+(pi*diameter*height)Total surface area = 1130.973355 or 1131 square feet to the nearest square foot.
diameter X pi = circumference circumference X height = area
-- You have to ask somebody for the radius of the sphere, in meters. If they tell you the diameter instead, then the radius is 1/2 of the diameter, in meters. -- Multiply (4) times (pi) times (the radius)2 . That's the surface area of the sphere, in square meters. -- Round the answer to the nearest square meter.
Generally, the heat transfer area of reference is considered to be the outside surface area of the tube. Therefore, figure the outside diameter of the tube to get the heat transfer area.