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If your ring has an outer radius of 8 mm and an inner one of 5 mm, you will have pi times (routside)2 minus pi times (rinside)2 or about 122.522 square millimeters of area on the top of the ring. Double that if you add in the surface area of the bottom. As to the sides (the inside and outside), we cannot calculate them without a thickness.

Q: What is the surface area if a cylindrical ring if its outside diameter is 16 mm and its inside diameter is 10 mm?

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S=pi x dxD S=3.14 x 3 x 40,82 S=384,5244 or rounded 385 mm

surface area = (pai) x (DO 2 - DI 2)/4 = 3.14 (16 x 16 - 10 x 10)/4 = 3.14 x 156 mm = 489.84 square mm

Inside area: pi1.51 square inches

Step One. Calculate the surface area of the inside of the vessel. Assume that the thickness of the vessel is negligible.Diameter is 20. Circumference is pi * diameter.C = 3.14159 * 20 = 62.8318 cmHeight = 14cm.Surface area = C * 14 = 879.6452 cm2Step Two. Calculate the cost of tinplating the surface area879.6452 * Re1 / 100 = CostCost = 8.796452 RE

A bowl has no vertex. An ordinary bowl has 5 faces and four edges. The five faces are: inside and outside of the base, inside and outside of the bowl, and the surface of the lip (a very thin circular band). The four edges are where the inside and outside of the curved side meet the base and the lip.

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In order to answer the question, its height is also required.

S=pi x dxD S=3.14 x 3 x 40,82 S=384,5244 or rounded 385 mm

surface area = (pai) x (DO 2 - DI 2)/4 = 3.14 (16 x 16 - 10 x 10)/4 = 3.14 x 156 mm = 489.84 square mm

To find the surface area of a cylindrical ring or torus, you can use the formula A = 2πrh, where r is the average radius of the ring and h is the height or thickness of the ring. In this case, the average radius is (16mm + 10mm)/2 = 13mm and h can be any desired value. Therefore, the surface area of the cylindrical ring or torus is 2π(13mm)(h).

inside

The diameter of a pipe is its width across an open end of the pipe. The inside diameter is the width measuring on the inside of the pipe; the outside diameter is the width measuring on the outside.______________________________________________________________________________________________________For a pipe of circular cross section, its nominal diameter is the diameter of the cross section.The inner diameter is the measuring on the inside of the pipeThe outside diameter is the measuring on the outside of the pipe.

take the outside diameter and subtract the thickness twice.

take the outside diameter and subtract the thickness twice.

take the outside diameter and subtract the thickness twice.

When dealing with pipe the volume is more important, therefore, I would use the inside diameter.

The circumference of that cylinder would be 31.4156 meters, and with a height of 4 meters, the outside surface of the sides would be 125.66 square meters. Does a cylinder have both an inside and outside surface? There is no thickness at all to the sides. Maybe it needs to be doubled, to be 251.32 square meters so we get both inside and outside surface, but I think not. A cylindrical *prism* would have a top and bottom, each having a surface of 78.54 square meters, for a total of 282.74 square meters.

Less than an inch.