S=pi x dxD
S=3.14 x 3 x 40,82
S=384,5244 or rounded 385 mm
surface area = (pai) x (DO 2 - DI 2)/4 = 3.14 (16 x 16 - 10 x 10)/4 = 3.14 x 156 mm = 489.84 square mm
If your ring has an outer radius of 8 mm and an inner one of 5 mm, you will have pi times (routside)2 minus pi times (rinside)2 or about 122.522 square millimeters of area on the top of the ring. Double that if you add in the surface area of the bottom. As to the sides (the inside and outside), we cannot calculate them without a thickness.
Inside area: pi1.51 square inches
Step One. Calculate the surface area of the inside of the vessel. Assume that the thickness of the vessel is negligible.Diameter is 20. Circumference is pi * diameter.C = 3.14159 * 20 = 62.8318 cmHeight = 14cm.Surface area = C * 14 = 879.6452 cm2Step Two. Calculate the cost of tinplating the surface area879.6452 * Re1 / 100 = CostCost = 8.796452 RE
A bowl has no vertex. An ordinary bowl has 5 faces and four edges. The five faces are: inside and outside of the base, inside and outside of the bowl, and the surface of the lip (a very thin circular band). The four edges are where the inside and outside of the curved side meet the base and the lip.
In order to answer the question, its height is also required.
surface area = (pai) x (DO 2 - DI 2)/4 = 3.14 (16 x 16 - 10 x 10)/4 = 3.14 x 156 mm = 489.84 square mm
If your ring has an outer radius of 8 mm and an inner one of 5 mm, you will have pi times (routside)2 minus pi times (rinside)2 or about 122.522 square millimeters of area on the top of the ring. Double that if you add in the surface area of the bottom. As to the sides (the inside and outside), we cannot calculate them without a thickness.
inside
To find the surface area of a cylindrical ring or torus, you can use the formula A = 2πrh, where r is the average radius of the ring and h is the height or thickness of the ring. In this case, the average radius is (16mm + 10mm)/2 = 13mm and h can be any desired value. Therefore, the surface area of the cylindrical ring or torus is 2π(13mm)(h).
The diameter of a pipe is its width across an open end of the pipe. The inside diameter is the width measuring on the inside of the pipe; the outside diameter is the width measuring on the outside.______________________________________________________________________________________________________For a pipe of circular cross section, its nominal diameter is the diameter of the cross section.The inner diameter is the measuring on the inside of the pipeThe outside diameter is the measuring on the outside of the pipe.
The electric field on the cylindrical Gaussian surface is oriented perpendicular to the surface, pointing outward or inward depending on the charge distribution inside the surface.
take the outside diameter and subtract the thickness twice.
take the outside diameter and subtract the thickness twice.
take the outside diameter and subtract the thickness twice.
The electric field inside an infinitely long cylindrical conductor with radius r and uniform surface charge density is zero.
When dealing with pipe the volume is more important, therefore, I would use the inside diameter.