The line of symmetry of y = 0 is x = 0.
the line of symmetry would occur at x=0
For y - 2y - 3y equals 0, y equals 0.
a = 3 and y = 0
y = 3x^(2) + 24x - 1 Differentiate and equate to '0' dy/dx = 6x - 24 = 0 6x - 24 = 0 6x = 24 x = 4 is the line of symmetry.
x = y = 0 ?
the line of symmetry would occur at x=0
y2 = 32x y = ±√32x the vertex is (0, 0) and the axis of symmetry is x-axis or y = 0
axis of symmetry is x=0 Vertex is (0,0) So the answer is : YES
For y - 2y - 3y equals 0, y equals 0.
a = 3 and y = 0
y = 3x^(2) + 24x - 1 Differentiate and equate to '0' dy/dx = 6x - 24 = 0 6x - 24 = 0 6x = 24 x = 4 is the line of symmetry.
x = y = 0 ?
The y-intercept equals 0.
y = 0x = y + 2plug 0 in for yx = 0 + 2x = 2
0
If: 3x+y = 4 and x+y = 0 Then: x = 2 and y = -2
Symmetry, which states that if A = B then B = A Put A = 4 and B = x + y