If: 3x+y = 4 and x+y = 0
Then: x = 2 and y = -2
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x2 - 3x - 4 = 0 so (x+1)(x-4) = 0, so x+1 = 0 and x-4 = 0, so x = -1 or 4
X intercept is the value of X when Y = 0 -5Y + 3X = 12 ley Y = 0 3x = 12 x = 4
Get in function form. - 3X - Y = 4 - 1(- Y = 3X + 4) Y = - 3X - 4 ----------------------------solve for X and Y by the 0 out method - 3X - 4 = 0 - 3X = 4 X = - 4/3 --------------- Y = - 3(0) - 4 Y = - 4 -------------- Draw a line linking those points.
X2 - 3X - 4 = 0factored(X + 1)(X - 4)----------------X = - 1X = 4-------------------(- 1, 0) and (4, 0)================solution set of X interception points
3x2+x-4 = 0 (3x+4)(x-1) = 0 Solutions: x = 1 and x = -4/3 By using the quadratic equation formula.