x2 - 3x - 4 = 0 so (x+1)(x-4) = 0, so x+1 = 0 and x-4 = 0, so x = -1 or 4
X intercept is the value of X when Y = 0 -5Y + 3X = 12 ley Y = 0 3x = 12 x = 4
Get in function form. - 3X - Y = 4 - 1(- Y = 3X + 4) Y = - 3X - 4 ----------------------------solve for X and Y by the 0 out method - 3X - 4 = 0 - 3X = 4 X = - 4/3 --------------- Y = - 3(0) - 4 Y = - 4 -------------- Draw a line linking those points.
X2 - 3X - 4 = 0factored(X + 1)(X - 4)----------------X = - 1X = 4-------------------(- 1, 0) and (4, 0)================solution set of X interception points
3x2+x-4 = 0 (3x+4)(x-1) = 0 Solutions: x = 1 and x = -4/3 By using the quadratic equation formula.
3x - 2x + 4 = 0 3x - 2x = -4 x = -4
3x + 4y - 4 = 0 y = -2 3x + 4(-2) - 4 = 0 3x - 8 - 4 = 0 3x = 12 x = 4 (4,-2)
x2 - 3x - 4 = 0 so (x+1)(x-4) = 0, so x+1 = 0 and x-4 = 0, so x = -1 or 4
x = - 4 and y = 0
x = y = 0 ?
3x2 + 10x - 8 = 0 3x2 + 12x - 2x - 8 = 0 3x(x + 4) - 2(x + 4) = 0 (3x - 2)(x + 4) = 0 So 3x - 2 = 0 or x + 4 = 0 so x = 2/3 or x = -4
3x-13x+4=0 -10x+4=0 4=10x 4/10=x simplified: x= 2/5
x = 0
x^2 + 3x + 3 = 7 x^2 + 3x - 4 = 0 (x - 1)(x + 4) = 0 x = 1 or x = -4
They are x = -1 and x = 4.
(3x+4)(3x-4)=0 x=±4/3
X intercept is the value of X when Y = 0 -5Y + 3X = 12 ley Y = 0 3x = 12 x = 4