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What else can I help you with?
Does 7(9-3p) 42p?
does 7(9-3p) = 42p
What is 42p-1 equals 5p plus 4?
42p-1 = 5p+4 42p = 5p+5 37p = 5 p = 5/37 p = 0.135135...
How much is needed to give 7 girls 6p each?
Amount needed: 7 times 6p = 42p
If three sweets costs 18p what will 7 cost?
42p 18/3 x 7 = 6 x 7 = 42
How many times greater is 4.20 than 42p?
4.20 = 420p 42*10 = 420p 10 times greater
What is the cost of 1kilogram 200g at 35p per kilogram?
To find the cost of 1 kilogram and 200 grams at 35 pence per kilogram, first convert 200 grams to kilograms by dividing by 1000 (since there are 1000 grams in a kilogram). This gives you 1.2 kilograms. Then, multiply the total weight (1.2 kg) by the cost per kilogram (35 pence) to find the total cost. Therefore, the cost of 1 kilogram and 200 grams at 35 pence per kilogram is 42 pence.
What fraction of a pound is 42p?
Well, honey, 42p is the same as 42 pence. There are 100 pence in a pound, so to find the fraction of a pound, you just divide 42 by 100. That gives you 42/100, which simplifies to 21/50. So, 42p is 21/50 of a pound. Hope that satisfies your curiosity, sweetheart.
What is the least number of coins needed to make 42p?
To make 42p using the least number of coins, you can use the following combination: 1 twenty pence coin, 1 ten pence coin, and 2 one pence coins. This totals 4 coins: 20p + 10p + 1p + 1p = 42p. Thus, the least number of coins needed is 4.
How much does 1kg 200g costs at 35p per kg?
the cost of one kg is 35p 200g is 1/5 of 1kg (1/5 of 1000) therefore you have to find 1/5 of 35p which equals 7. Therefore 35p + 7p = 42p
What is 8p plus 4 equals 10 plus 6p?
algebra8p +4 = 10 +6p+8p - 6p = +10 - 42p = 6p = 3
What can you buy for three cents?
If your haveing a big party with all your mate then i suggest going to teso 1 huge bottle of diet coke is 50p each so you can gete 6 0f them or a pack of extra gum is 42p each go on treat your self!
What is the Product for (3p 7)(3p 7)?
To find the product of (3p + 7)(3p + 7), you can use the formula for the square of a binomial, which is ( (a + b)^2 = a^2 + 2ab + b^2 ). In this case, ( a = 3p ) and ( b = 7 ). Therefore, the product is: [ (3p)^2 + 2(3p)(7) + 7^2 = 9p^2 + 42p + 49. ] So, the final result is ( 9p^2 + 42p + 49 ).
