Q: What is the total of digits used in numbers from 51 to 5001?

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Not 2 numbers - 2 digits. The digits 0 and 1.

381 digits.

It is usually 4 digits. Some banks offer pin numbers that are more than 4 digits long.

This is permutations with repetition. The answer is 4^4 = 256 total permutations. Since 2 of the digits used are odd (and 2 are even), then half of the possibilities will be odd: 128 odd numbers.

There are 10 digits in our number system. The symbols 0,1,2,3,4,5,6,7,8,and 9 are the digits used to create numbers.

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Not 2 numbers - 2 digits. The digits 0 and 1.

Three digits.

381 digits.

It is usually 4 digits. Some banks offer pin numbers that are more than 4 digits long.

This is permutations with repetition. The answer is 4^4 = 256 total permutations. Since 2 of the digits used are odd (and 2 are even), then half of the possibilities will be odd: 128 odd numbers.

There are 10 digits in our number system. The symbols 0,1,2,3,4,5,6,7,8,and 9 are the digits used to create numbers.

Octal (base 8) uses the digits 0 - 7.

There are only two digits used in binary: 0 (zero) and 1 (one).

Binary uses only the digits 0 and 1.

0 and 1

Assuming each of the given digits can be used only once, the answer is 24. If not, the answer is infinity.

There are a total of 900 3-digt numbers (100 thru 999); Of these there are 9x9x8 = 648 numbers that do not contain repeating digits (first position: 9 possibilities, second place 9 possibilities; the 10 digits minus the one used in the first place. and third place 8 possibilities; 10 digits minus the two used in the first and second places) So, there should be 900-648=252 3-digit numbers with at least one repeating digit.