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Q: What is the value of sqrt 4x2?

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Sqrt(24x4)/Sqrt(3x) = Sqrt(24x4/3x) = Sqrt(8x3) = Sqrt(4x2*2x) = 2x*sqrt(2x)

sqrt(24x4) / sqrt(3x) = sqrt(24x4/3x) = sqrt(8x3) = sqrt(2x times 4x2) = 2x sqrt(2x) or (2x)1.5

Y = 4x2 + 6x - 1Use the pq-formula:x = -4/2 +- sqrt ((4/2)2 -(-1))x = -2 +- sqrt((16/4) +1)x = -2 +- sqrt(4 +1)x1 = -2 + sqrt(5)x2 = -2 - sqrt(5)

sqrt(4)=2 sqrt(169)=13 (2x+13)(2x-13)

Reading this as: 4x2-6=2x2 This implies that: -6=-2x2 3=x2 x=sqrt(3) and x=-sqrt(3) So x can equal plus or minus the square root of 3

The absolute value is sqrt(72 + 12) = sqrt(49 + 1) = sqrt(50) or 5*sqrt(2) = 7.071 approx.

1

-i/sqrt(2) -i/sqrt(2)

(sqrt(6)-sqrt(2))/4

-2

The absolute value of 7Ã‚Â± 5i = sqrt(72 + 52) = sqrt(49 + 25) = sqrt(74) = 8.602, approx.

Whether or not the expression can be simplified depends on the value of a. In general, sqrt(2a) = sqrt(2)*sqrt(a).

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