sqrt(4x2) = ± 2x
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Sqrt(24x4)/Sqrt(3x) = Sqrt(24x4/3x) = Sqrt(8x3) = Sqrt(4x2*2x) = 2x*sqrt(2x)
Reading this as: 4x2-6=2x2 This implies that: -6=-2x2 3=x2 x=sqrt(3) and x=-sqrt(3) So x can equal plus or minus the square root of 3
The absolute value of 7± 5i = sqrt(72 + 52) = sqrt(49 + 25) = sqrt(74) = 8.602, approx.
(sqrt(6)-sqrt(2))/4
(1+sqrt(3))/(2 sqrt(2))