3x + 6x +1 = 10 9x = 10 - 1 9x = 9 x = 1
x=4 y=1 Therefore, 6x+5y=? Just substitute, and get 6*4+5*1=29
If: 6x-4+7 = 5 Then: x = 1/3
4x2-4x+1 = (2x-1)(2x-1)
x = 2, y = 1
4x2 + 5x + 1 - 4x2 - 6x = - x + 1 or 1 - x4x2 + 5x + 1 - 4x2 - 6x = - x + 1 or 1 - x4x2 + 5x + 1 - 4x2 - 6x = - x + 1 or 1 - x4x2 + 5x + 1 - 4x2 - 6x = - x + 1 or 1 - x
8x3 + 4x2 + 6x + 3 = 4x2(2x + 1) + 3(2x + 1) = (2x + 1)(4x2 + 3)
This is how I did it:8x3+4x2+6x+3[8x3+4x2]+[6x+3][(4x2)(2x+1)]+[(3)(2x+1)]....as you can see, this is in the general form of ab+cb, which factored is b(a+c), so:(2x+1)(4x2+3)
2(x + 1)(2x + 1)
2(4x2 + 6x - 1)
No answers in integers, quadratic formula gives roots as 1.31 and -0.19
2x + 9 = 6x + 1 9 - 1 = 6x - 2x 8 = 4x x = 2
-((4x + 1)(x - 1))
6x = 1 x = 1/6
-5x+1 = 6x -5x-6x = -1 -11x = -1 x = 1/11
3x + 6x +1 = 10 9x = 10 - 1 9x = 9 x = 1
1/6