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It is 10.
Just substitute 4 in for X. 13 - 2(4) 13 - 8 = 5 ===
If x = 3, then x + 10 would be 3 + 10, which is 13.
4x^2 + 9 is a prime algebraic expression. Its numerical value may be prime of not - depending on the value of x.For x = 1, the value of the expression is 13 - a prime whereasfor x = 2, the value of the expression is 25 - not a prime.
13 x 10 = 130
It is 10.
Just substitute 4 in for X. 13 - 2(4) 13 - 8 = 5 ===
x+10>13 it wouldn't be x+10-13 ??
7
If x = 3, then x + 10 would be 3 + 10, which is 13.
4x^2 + 9 is a prime algebraic expression. Its numerical value may be prime of not - depending on the value of x.For x = 1, the value of the expression is 13 - a prime whereasfor x = 2, the value of the expression is 25 - not a prime.
It means that if you know the value of a variable, you replace every occurence of the variable with the value. For example, if x = 10, and you have the expression x2 + 5x - 3, you replace every x with 10, to get 102 + 5(10) - 3.It means that if you know the value of a variable, you replace every occurence of the variable with the value. For example, if x = 10, and you have the expression x2 + 5x - 3, you replace every x with 10, to get 102 + 5(10) - 3.It means that if you know the value of a variable, you replace every occurence of the variable with the value. For example, if x = 10, and you have the expression x2 + 5x - 3, you replace every x with 10, to get 102 + 5(10) - 3.It means that if you know the value of a variable, you replace every occurence of the variable with the value. For example, if x = 10, and you have the expression x2 + 5x - 3, you replace every x with 10, to get 102 + 5(10) - 3.
13 x 10 = 130
As an algebraic expression it is simply: 18-x
The base of log, if unspecified, is taken to be 10 so you would be finding the value of the logarithm of 5 to the base 10.This is the value x, such that 10^x = 5.
x + (13-10)
If x stays the same the expression stays the same. Since the expression involves negative x, the value of the expression decreases as x increases.