It means that if you know the value of a variable, you replace every occurence of the variable with the value. For example, if x = 10, and you have the expression x2 + 5x - 3, you replace every x with 10, to get 102 + 5(10) - 3.
It means that if you know the value of a variable, you replace every occurence of the variable with the value. For example, if x = 10, and you have the expression x2 + 5x - 3, you replace every x with 10, to get 102 + 5(10) - 3.
It means that if you know the value of a variable, you replace every occurence of the variable with the value. For example, if x = 10, and you have the expression x2 + 5x - 3, you replace every x with 10, to get 102 + 5(10) - 3.
It means that if you know the value of a variable, you replace every occurence of the variable with the value. For example, if x = 10, and you have the expression x2 + 5x - 3, you replace every x with 10, to get 102 + 5(10) - 3.
To substitute values into the simple interest formula, use the formula (I = P \times r \times t), where (I) is the interest, (P) is the principal amount, (r) is the annual interest rate (in decimal form), and (t) is the time in years. For example, if (P = 1000), (r = 0.05), and (t = 3), you would substitute these values in to get (I = 1000 \times 0.05 \times 3). This simplifies to (I = 150). Thus, the interest earned over three years would be $150.
They are, when appropriate.
You substitute the variable for its value. Or you substitute the variables for each of the values.
You must substitute values for the variable.
first wright the eqn then write their concentration at initial , used and then equilibrium. using the formula substitute the values given at equilibrium.
To calculate the surface area of a cylinder, you can use the formula ( SA = 2\pi r(h + r) ), where ( r ) is the radius and ( h ) is the height of the cylinder. If you provide the values for the radius and height, I can calculate the surface area for you. Otherwise, you can substitute the values into the formula to find the answer to the nearest hundredth.
Choose some values for x. Then calculate the corresponding values of y using the formula. Put these values in a table.Choose some values for x. Then calculate the corresponding values of y using the formula. Put these values in a table.Choose some values for x. Then calculate the corresponding values of y using the formula. Put these values in a table.Choose some values for x. Then calculate the corresponding values of y using the formula. Put these values in a table.
To calculate the perimeter of an isosceles triangle, you add the lengths of all three sides. If the lengths of the two equal sides are each ( a ) and the base is ( b ), the formula is ( P = 2a + b ). Simply substitute the values of ( a ) and ( b ) into the formula to find the perimeter.
Substitute the values of the variables into the inequality. If the inequality is true then they are a solution, if not, they are not.Substitute the values of the variables into the inequality. If the inequality is true then they are a solution, if not, they are not.Substitute the values of the variables into the inequality. If the inequality is true then they are a solution, if not, they are not.Substitute the values of the variables into the inequality. If the inequality is true then they are a solution, if not, they are not.
-- First, write the quadratic formula on the back of your hand:x = 1/2A [ -B ± sqrt(B2 - 4AC) ]-- Then, stare at your equation until it dawns on you thatA = 12B = -77C = -20-- Substitute these values of 'A', 'B', and 'C' into the quadratic formula,evaluate it for the two values of 'x', and the two solutions practicallyfall out on the floor and surrender, on their own.
from the equation using the formula -b/2a to find x value. from there substitute values of x before and after in equation.for example if x is 2 use other x values as 1 and 3.
It is usually not all numbers. It can be all variables, such as area of a rectangle = L*B where L and B are the length and breadth. But to use the formula it is necessary to substitute the numerical values of the variables.