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To find the vertex of the quadratic function ( y = x^2 - 4x + 1 ), we can use the vertex formula ( x = -\frac{b}{2a} ), where ( a = 1 ) and ( b = -4 ). This gives ( x = -\frac{-4}{2 \cdot 1} = 2 ). Substituting ( x = 2 ) back into the equation, we find ( y = 2^2 - 4(2) + 1 = -1 ). Thus, the vertex of the function is at the point ( (2, -1) ).
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Vertex for y equals x2 plus 2x plus 1?
The vertex is at (-1,0).
What is the vertex of y equals x plus 1?
y = x +1 is the equation of a straight line and so has no vertex.
What is the x-coordinant of the vertex in the function y equals x2 plus 14 plus 21?
y = x2 + 14x + 21 a = 1, b = 14 x = -b/2a = -14/2*1 = -7
What is the vertex of y equals 2x squared 4x 1?
Need signs between terms.
Where is the vertex coordinate of the parabola y equals 24 -6x -3x squared when plotted on the Cartesian plane?
The vertex coordinate point of the vertex of the parabola y = 24-6x-3x^2 when plotted on the Cartesian plane is at (-1, 27) which can also be found by completing the square.
Vertex for y equals x2 plus 2x plus 1?
The vertex is at (-1,0).
What is y equals x2 plus 2x plus 1 on a graph?
Interpreting that function as y=x2+2x+1, the graph of this function would be a parabola that opens upward. It would be equivalent to y=(x+1)2. Its vertex would be at (-1,0) and this vertex would be the parabola's only zero.
What is the vertex of y equals x plus 1?
y = x +1 is the equation of a straight line and so has no vertex.
What is the vertex of the equation y equals 2x-1?
3
What is the x-coordinant of the vertex in the function y equals x2 plus 14 plus 21?
y = x2 + 14x + 21 a = 1, b = 14 x = -b/2a = -14/2*1 = -7
What is the vertex of y equals 2x squared 4x 1?
Need signs between terms.
Where is the vertex coordinate of the parabola y equals 24 -6x -3x squared when plotted on the Cartesian plane?
The vertex coordinate point of the vertex of the parabola y = 24-6x-3x^2 when plotted on the Cartesian plane is at (-1, 27) which can also be found by completing the square.
What is the line of symmetry and the vertex when y equals 3x squared plus 2x minus 1?
y = 3x2+2x-1 Line of symmetry: x = -1/3 Vertex coordinate: (-1/3, -4/3)
What is the vertex and the axis of symmetry for the function y equals x2 plus 4x plus 1?
Take the derivative: y' = 2x + 4. Set equal to zero: 2x + 4 = 0 --> x = -2. Substitute into original and y = -3. Axis of symmetry is x = -2. Vertex is (-2,-3)
What is the vertex of 1?
1 is a number. It does not have a vertex!
What is the vertex of the function y equals 2 x 2 plus 8x plus 1?
If you meant, your two equations are y=2x+2 and y= 8x+1 your vertex will be at x=1/6 and y=7/3 you can plug these in and they will check out. but if you meant, y=(2x2) +8x+1 y=4+8x+1 y=8x+5 and then you only have one line so there will be no vertex. but the y intercept is at (0, 5) and your x-intercept at (-5/8, 0) if neither are these are what you are saying, sorry, and maybe try and repost and I will help you out.
What is the vertex of the quadratic function f(x)x2 plus c?
The vertex of the quadratic function ( f(x) = ax^2 + bx + c ) can be found using the formula ( x = -\frac{b}{2a} ). Once you determine the x-coordinate of the vertex, you can substitute it back into the function to find the corresponding y-coordinate. Therefore, the vertex is at the point ( \left(-\frac{b}{2a}, f\left(-\frac{b}{2a}\right)\right) ). If the function is given as ( f(x) = x^2 + c ) (where ( a = 1 ) and ( b = 0 )), the vertex simplifies to ( (0, c) ).
