If you meant, your two equations are y=2x+2 and y= 8x+1
your vertex will be at x=1/6 and y=7/3
you can plug these in and they will check out.
but if you meant, y=(2x2) +8x+1
y=4+8x+1
y=8x+5 and then you only have one line so there will be no vertex. but the y intercept is at (0, 5) and your x-intercept at (-5/8, 0)
if neither are these are what you are saying, sorry, and maybe try and repost and I will help you out.
If -8x+3=251, then 8x=-248. Therefore, x=-31.
8x + 3 = 50 8x = 47x = 47/8x= 5 and 7/8ths
8x - 9 = 11x + 12 8x = 11x + 21 -3x = 21 x = -7
8x-4 = -7+5x 8x-5x = -7+4 3x = -3 x = -1
(8 + 4) x 5...
The vertex has a minimum value of (-4, -11)
Y = X2 - 8X + 12set to 0X2- 8X + 12 = 0X2 - 8X = - 12halve the coefficient of the linear term, ( - 8 ), square it and add it to both sidesX2 - 8X + 16 = - 12 + 16factor on the left and gather term on the right(X - 4)2 = 4(X - 4)2 - 4 = 0================vertex form(4, - 4)=======vertex
x^2-8x+3 = x^2-8x+16-16+3 = (x-4)^2-13 y=(x-4)^2 -13 The vertex is (4,-13).
Y-8x plus 9y equals 10y-8x.
(-4,-1)
8x plus 4y equals 5 is 8x + 4y = 5.
The vertex form is y = (x - 4)2 + 13
f(x)= (4 - 5y)/8 f(y)= (4 - 8x)/5
A linear relationship. Added: And a function.
No.
- 8x + 8x = 0 so question is meaningless.
8x-7 plus 2x equals 6 plus 5x plus 2?