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There is no single standard here; sometimes, percentages are used (either volume or mass percentages; the numbers may be different for the same mixture, due to different densities); mass per volume (e.g., grams per liter); or moles per volume (e.g., moles per liter).
You haven't given the volume of solution. M means moles per liter. First off you divide 5 by 1000 and multiply by the amount of mls you have to find out how many moles that you have. then multiply by molecular weight of NaCl
molarity is the number of moles dissolved per volume of a solution in dm cube molarity=mass of solute in gram __________________ 1 * _________________ molecular mass of solute volume of solution in dm cube OR molarity=no.of moles ________________ volume of solution in dm cube
(Micrograms per litre)/(gram molecular weight of solute) = (micromoles per litre).
Use general gas law: V = n.R.T / pin which:n = number of moles (to be filled in)R = gas constant = 8.20*10-2 (L.atm.K-1.mol-1)T = tempeature (K) = 273 K (stand.T)p = pressure (atm) = 1.00 atm (stand.P)then the calculated volume is in Liter
The volume is 44,828 L at 0 oC.
This volume is 6,197 399 5 at 25 0C.
Molarity is moles/liter, so in order to find the moles of a substance in a given volume, simply multiply molarity with volume (in liters). n=M*V
54 liters at STP (standard temperature and pressure)
I would assume chlorine gas and standard temperature an atmospheric pressure. Using the ideal gas equation. PV = nRT (1 atm)(X volume) = (2.4 moles Cl2)(0.08206 Mol*K/L*atm)(298.15 K) Volume = 59 Liters of chlorine gas --------------------------------------------
liter = unit of volume mole = unit of concentration
The volume is 254,82 L.
The mass of 2,4 moles of chlorine is 84,08 g.
Molarity is defined as moles solute/liter of solution6 moles/2 liters solution = 3 molar NOTE: This assumes no volume change and 2L is the final volume of solution.
At STP, 1 mole of gas occupies a volume of 22.4 liters. Thus, 4/5 moles of gas will occupy .8*22.4 liters.
Molarity is calculated as moles of solute divided by volume of solution in liters. In this case, you have 2 moles of sodium chloride in a 0.5 liter solution. So the molarity would be 2 moles / 0.5 L = 4 M.
75,10 g of chlorine = 2,1183 moles