the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
the perimeter of a rectangle is 700 yards. what are the dimensions of the rectangle if the lenght is 80 yards more than the width?
Perimeter = length + width + length + width = 2 x (length + width) Given: perimeter = 22in length = width + 3in Thus 22 = 2 x (width + 3 + width) 11 = 2 x width + 3 8 = 2 x width 4 = width So the width is 4in.
You forgot to put in the length of the rectangle's perimeter.
length + width = 20/2 = 10 length = 7cm, width = 3cm
Let the width of rectangle is w cm (Length is 12 cm more) so length is w + 12 Perimeter = 16 times of width 2 (length + width) = 16 * width Rest of the homework, do yourself.
The dimensions of the rectangle are 21 units by 9 units
Length = 20 m and width = 9 m
The length could be 3 cm (width = 1 cm), with a perimeter of 8 cm, which is not more than 72 cm. Or it could be 6 cm (w = 2 cm, perimeter = 16 cm).
The length is 14 cm
Do-it-in-your-head method: Length + width is half the perimeter which is 27 inches; 27 minus 6 is 21 and one-third of 21 is 7 which is the width. (Length = 2 x 7 + 6 = 20)
You don't have enough information to find the exact length of the width, but the width has to be less then 7.5 if it smaller then the length.
Length of rectangle: 7.9 cm Width of rectangle: 1.3 cm Area of rectangle: 7.9 times 1.3 = 10.27 square cm
Width = 10cm.. i think Length = 68cm
228 feet is the perimeter.
The length of the rectangle is 27 meters and the width is 19 meters.
length + width = 1/2 x 60 in = 30 inches The length is 3 inches more than than the width, so length is 16.5 inches and width is 13.5 inches.
18.4cm by 22.4cm
Width = 9 inches Length = 30 inches