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The perimeter of a rectangle is 97m The width is 2m more than half the length Find the length and width?
Let the width be 1/2x+2 and the length be x: 2(width+length) = perimeter 2(1/2x+2+x) = 97m x+4+2x = 97 x+2x = 97-4 3x = 93 x = 31 Therefore: length = 31m and width = 17.5m Check: 31+31+17.5+17.5 = 97m
Length of a box 2x plus 1 width is x. x equals 2.5 What is the surface area?
The answer is 15 like its given (2x+1) length and X is width .whereas X = 2.5 so the surface area of a box is Length X Width. putting the value of X = 2.5 in (2X2.5 +1)(2.5)=15
What is the length and width of a rectangle that has a perimeter of 120 cm and its one fifth as much as the length?
1/5 of 120 = 24 =length and let the width be x: Perimeter = 2(24+x) = 120 48+2x = 120 2x = 120-48 2x = 72 x = 36 Therefore: length = 24 cm and width = 36 cm Check: 24+24+36+36 = 120 cm
What is the length of the rectangle if the perimeter is 134m and the length is 7 more than half the width?
Let the length be (1/2x+7) and the width be x: Perimeter = 2(length+width) = 134 2(1/2x+7+x) = 134 Multiply out the brackets: x+14+2x = 134 Collect like terms and subtract 14 from both sides: 3x = 120 Divide both sides by 3: x = 40 Therefore: length = 27 meters and width = 40 meters Check: 27+27+40+40 = 134 meters
The length of an airport is 1 mile more than twice the width the area is 21 square miles identify the legth and width of the airport?
Let the length be (2x+1) and the width be x: length*width = area (2x+1)*x = 21 square miles 2x2+x-21 = 0 Solving the above quadratic equation works out as: x = -7/2 or x = 3 it must be the latter because dimensions can't be negative. Therefore: length = 7 miles and width = 3 miles
What is the perimeter of a rectange where width equals x-3 and length equals x plus 1?
Perimeter = 2(Length + Width) = 2*(x+1 + x-3) =2*(2x - 2) = 4*(x - 1)
The perimeter of a rectangle is 97m The width is 2m more than half the length Find the length and width?
Let the width be 1/2x+2 and the length be x: 2(width+length) = perimeter 2(1/2x+2+x) = 97m x+4+2x = 97 x+2x = 97-4 3x = 93 x = 31 Therefore: length = 31m and width = 17.5m Check: 31+31+17.5+17.5 = 97m
Length of a box 2x plus 1 width is x. x equals 2.5 What is the surface area?
The answer is 15 like its given (2x+1) length and X is width .whereas X = 2.5 so the surface area of a box is Length X Width. putting the value of X = 2.5 in (2X2.5 +1)(2.5)=15
What would be the dimensions of the rectangle if the length is yd more than twice the width the area is 452?
Let the length be 2x+1 and the width be x:- And so: (2x+1) times x = 452 or 2x^2 +x -452 = 0 Using the quadratic equation formula x has a positive value of: 14.78537495 Width = 14.78537495 yds and length is 2*(14.78537495)+1 = 30.5707499 yds Check: width times length = 451.9999998 which rounds to 452 square yards
The top floor is rectangular and has perimeter 520 ft The width of top floor measres 20 ft more than one-half its length What are the dimensions of the top floor?
Let the width be 1/2x+20 and the length be x: 2(width+length) = perimeter 2(1/2x+20+x) = 520 ft x+40+2x = 520 x+2x = 520-40 3x = 480 x = 160 Therefore: width = 100 ft and length = 160 ft Check: 2(100+160) = 520 ft
What is the length and width of a rectangle that has a perimeter of 120 cm and its one fifth as much as the length?
1/5 of 120 = 24 =length and let the width be x: Perimeter = 2(24+x) = 120 48+2x = 120 2x = 120-48 2x = 72 x = 36 Therefore: length = 24 cm and width = 36 cm Check: 24+24+36+36 = 120 cm
What is the length of the rectangle if the perimeter is 134m and the length is 7 more than half the width?
Let the length be (1/2x+7) and the width be x: Perimeter = 2(length+width) = 134 2(1/2x+7+x) = 134 Multiply out the brackets: x+14+2x = 134 Collect like terms and subtract 14 from both sides: 3x = 120 Divide both sides by 3: x = 40 Therefore: length = 27 meters and width = 40 meters Check: 27+27+40+40 = 134 meters
The length of an airport is 1 mile more than twice the width the area is 21 square miles identify the legth and width of the airport?
Let the length be (2x+1) and the width be x: length*width = area (2x+1)*x = 21 square miles 2x2+x-21 = 0 Solving the above quadratic equation works out as: x = -7/2 or x = 3 it must be the latter because dimensions can't be negative. Therefore: length = 7 miles and width = 3 miles
When the perimeter of a rectangle is fifty two inches the length is three less than twice the width Fin the dimensions?
Let the length be 2x-3 and the width be x: 2(length+width) = perimeter 2(2x-3+x) = 52 inches 4x-6+2x = 52 4x+2x = 52+6 6x = 58 x = 9 and 2/3 Therefore: length = 16 and 1/3 inches and width = 9 and 2/3 inches Check: 2(16+1/3+9+2/3) = 52 inches
The perimeter of a length is 122 meters and the length is one more meter than twice the width what is the length?
Let the breadth = xSo, length = 2x+1Thus perimeter will be,2(2x+1+x)=122= 6x+2=122So, 6x=122-2=120So, x= 120/6=20Therefore length=2x+1=2(20)+1=41
How do you find the length and width when the area is 8x2 plus 2x-3?
Given the area, there is no justification for assuming that it refers to a rectangular area: it could be circular, triangular or an even irregular shape.However, if you make the totally unjustified assumption that it is a rectangle, then8x^2 + 2x - 3 = (4x + 3)*(2x - 1)Therefore the two lengths are 4x + 3 and 2x - 1.Conventionally, the length is the larger of the two sides and so, for positive solutions, the length is 4x + 3 units while the width is 2x - 1 units.
The length of a rectangle is 1cm less than twice the width find the length and width if the perimeter is 22 cm?
Let W = x. Then, the length is 2x - 1. So we can write: P = 2L + 2W or P/2 = L + W substitute the given values 22/2 = (2x -1) + x 11 = 3x - 1 add 1 to both sides 12 = 3x divide by 3 to both sides 4 = x 2x - 1 = 2(4) - 1 = 7 Thus the width is 4 cm and the length is 7 cm. Check:
